Please click on the file and answer ASAP.
1 answer:
You might be interested in
We have that
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>
triangle ABC coordinates
A (0,2) B(2,4) C(0,0)
triangle DEF coordinates
D (2,0) E ( 4,4) F (4,2)
using a graph tool
see the attached figure
therefore
Line 1<span> Segment AC equals 2. Segment FE equals 2. Segment AC is congruent to segment FE
</span>so
Segment AC equals 2-------> is correct
Segment FE equals 2-----> is correct
Segment AC is congruent to segment FE------> is correct
<span>Line 2 ∠A ≅ ∠F------> is correct
</span>
<span>Line 3 Length of segment AB. A (0, 2) B (2, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, d equals square root of quantity 0 minus 2 all squared plus quantity 2 minus 4 all squared, d equals square root of negative 2 squared plus negative 2 squared, d equals square root of 4 plus 4, d equals square root of 8 segment AB = 2.83
</span>
find the distance AB
d=√[(4-2)²+(2-0)²]--------> d=√[4+4]-----> d=√8-----> d=2.83
AB=2.83
so
Line 3 is correct
<span>Line 4 Length of segment DE. D (2, 0) E (4, 4) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared, d equals square root of quantity 2 minus 4 all squared plus quantity 0 minus 4 all squared, d equals square root of negative 2 squared plus negative 4 squared, d equals square root of 4 plus 16, then d equals square root of 20 segment DE = 4.47
</span>
find the distance DE
d=√[(4-0)²+(4-2)²]--------> d=√[16+4]-----> d=√20-----> d=4.47
DE=4.47
so
Line 4------> is correct
<span>Line 5 segment AB is congruent with segment DE
AB is not congruent with DE
so
Line 5 is not correct
therefore
the answer is
</span><span>the student make the first mistake in line 5</span><span>
</span>
ANSWER
EXPLANATION
The complex number shown has coordinates (2,-2)
or
The modulus is
The argument is
The polar form is
The first option is correct.
Answer:
b)0, yes
Step-by-step explanation:
Given:
Vectors (4,8) . (6,-3)
Finding inner product of vectors:
= 4x6 + 8x-3
=24-24
=0
Now to check the angle between them using formula a.b=|a|.|b|cosθ
|a|=
=8.9
|b|=
=6.7
Putting values of a.b=0 and |a|=8.9, |b|=6.7 in a.b=|a|.|b|cosθ we get,
0= 8.9(6.7)cosθ
cosθ =0
θ=90 degrees
Hence the two vectors are perpendicular !
General Idea:
W hen we are given a point P(x, y) centered at origin with a scale factor of k, then the dilated point will be given by P' (kx, ky)
When, then P' is enlargement of P
When , then P' is reduction of P
Applying the concept:
In the diagram given A'B'C' is enlargement of ABC. So the correct option will be option A. , enlargement