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dangina [55]
2 years ago
9

Consider a resistor (R=1000 kΩ) and a capacitor (C=1μF) connected in series. This configuration is connected in series to a batt

ery with an emf of 10 V.
After the capacitor is charged to its maximum value, the capacitor and resistor are disconnected from the battery and from each other. Then they are connected in parallel, so that the capacitor discharges through the resistor. How long will it take for the voltage across the capacitor to drop to 2.50 V?
Physics
1 answer:
BabaBlast [244]2 years ago
5 0

Answer:

The maximum pressure is 10 V from across condenser.The highest charge mostly on condenser. 
Vc  = 10 x 1mf

= 10 ^ - 5C

The time it takes for the condenser to be 5 V different.        
Thus we have, 0.69 x 10 ^ - 3 seconds.

You might be interested in
Which of the following statements best characterizes the surface of the planet Mars?The surface of Mars is continuously resurfac
butalik [34]

All the big volcanoes are in the northern hemisphere of Mars, and most of the craters are in the southern hemisphere is of the following statements that best characterizes the surface of the planet Mars.


Hope this helps,

Davinia.

4 0
4 years ago
Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelera
svetlana [45]

Answer:

(a) Fₓ = 0 N

F_y = 9.08 N

(b)

(a) Fₓ = 0 N

<u></u>F_y = 9.08 N

(c) F_y = 0 N

Fₓ = 9.08 N

Explanation:

The magnitude of the force will remain the same in each case, which is given as follows:

F = ma (Newton's Second Law)

where,

F = force = ?

m = mass = 4.54 kg

a = acceleration = 2 m/s²

Therefore,

F = (4.54 kg)(2 m/s²)

F = 9.08 N

Now, we come to each scenario:

(a)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

<u>Fₓ = 0 N</u>

For upward direction the force will be positive:

<u></u>F_y<u> = 9.08 N</u>

<u></u>

(b)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

<u>Fₓ = 0 N</u>

For upward direction the force will be negative:

<u></u>F_y<u> = - 9.08 N</u>

<u></u>

(c)

Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:

<u></u>F_y<u> = 0 N</u>

<u>Fₓ = 9.08 N</u>

3 0
3 years ago
Una persona de 80kg intenta bajar de peso subiendo una montaña para quemar el equilante a una rebanada de pastel de chocolate (7
SCORPION-xisa [38]

Answer:

Explanation:

An 80kg person tries to lose weight by climbing a mountain to burn the equivalent of a large slice of a rich chocolate cake (700kcl). How high should you climb?

Given that,

A person of mass

M = 80kg

The person is climbing a stair case and he burn an energy of 700 kcl

We know that 1kcl = 4184J

Then, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10^6 J

We want to find height of stairs the person will climb when he Loss 700kcl. The energy he burns will be converted to the potential energy

P.E is calculated using

P.E = mgh

Where

m is mass in kg

g is gravitational constant g = 9.81m/s2

h is the height of stairs he climb in metre

Then,

P.E = energy burn

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10^6

h = (2.9288 × 10^6) / (80 × 9.81)

h = 3731.91m

So, the person will climb 3731.91m before he losses 700kcl

In espanyol

Dado que,

Una persona de masa

M = 80 kg

La persona está subiendo una escalera y quema una energía de 700 kcl.

Sabemos que 1kcl = 4184J

Entonces, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10 ^ 6 J

Queremos encontrar la altura de las escaleras que la persona subirá cuando pierda 700kcl. La energía que quema se convertirá en energía potencial.

P.E se calcula utilizando

P.E = mgh

Dónde

m es masa en kg

g es constante gravitacional g = 9.81m / s2

h es la altura de las escaleras que sube en metros

Entonces,

P.E = quema de energía

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10 ^ 6

h = (2.9288 × 10 ^ 6) / (80 × 9.81)

h = 3731.91m

Entonces, la persona subirá 3731.91m antes de perder 700kcl

5 0
4 years ago
g If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resi
Anettt [7]
<h2>Question:</h2>

In this circuit the resistance R1 is 3Ω, R2 is 7Ω, and R3 is 7Ω. If this combination of resistors were to be replaced by a single resistor with an equivalent resistance, what should that resistance be?

Answer:

9.1Ω

Explanation:

The circuit diagram has been attached to this response.

(i) From the diagram, resistors R1 and R2 are connected in parallel to each other. The reciprocal of their equivalent resistance, say Rₓ, is the sum of the reciprocals of the resistances of each of them. i.e

\frac{1}{R_X} = \frac{1}{R_1} + \frac{1}{R_2}

=> R_{X} = \frac{R_1 * R_2}{R_1 + R_2}             ------------(i)

From the question;

R1 = 3Ω,

R2 = 7Ω

Substitute these values into equation (i) as follows;

R_{X} = \frac{3 * 7}{3 + 7}

R_{X} = \frac{21}{10}

R_{X} = 2.1Ω

(ii) Now, since we have found the equivalent resistance (Rₓ) of R1 and R2, this resistance (Rₓ) is in series with the third resistor. i.e Rₓ and R3 are connected in series. This is shown in the second image attached to this response.

Because these resistors are connected in series, they can be replaced by a single resistor with an equivalent resistance R. Where R is the sum of the resistances of the two resistors: Rₓ and R3. i.e

R = Rₓ + R3

Rₓ = 2.1Ω

R3 = 7Ω

=> R = 2.1Ω + 7Ω = 9.1Ω

Therefore, the combination of the resistors R1, R2 and R3 can be replaced with a single resistor with an equivalent resistance of 9.1Ω

4 0
3 years ago
A spherical snowball is melting in such a way that its radius is decreasing at a rate of 0.1 cm/min. At what rate is the volume
Ne4ueva [31]

Answer: 80.384 cubic cm /min

Explanation:

Let V denote the volume and r denotes the radius of the spherical snowball .

Given : \dfrac{dr}{dt}=-0.1\text{cm/min}

We know that the volume of a sphere is given by :-

V=\dfrac{4}{3}\pi r^3

Differentiating on the both sides w.r.t. t (time) ,w e get

\dfrac{dV}{dt}=\dfrac{4}{3}\pi(3r^2)\dfrac{dr}{dt}\\\\\Rightarrow\ \dfrac{dV}{dt}=4\pi r^2 (-0.1)=-0.4\pi r^2

When r= 8 cm

\dfrac{dV}{dt}=-0.4(3.14)(8)^2=-80.384

Hence, the volume of the snowball decreasing at the rate of 80.384 cubic cm /min.

6 0
3 years ago
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