3 years ago

What is the difference between an open and closed circuit?

Physics

1 answer:

exis [7]3 years ago

7 0

A closed circle means the number is included and an open circle means its not.

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A forward honzontal force of 50 N is applied to a crate. A second horizontal force o

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Answer:

Explanation:

magnitude: 180-50=130N

Direction: in the direction same as the second horizontal force

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3 years ago

-List ten different waves that you encounter in everyday life. Be specific, don't just say "sound

Nady [450]

Answer:

1.Radio waves from using your TV.

2. microwaves you are in satellites.

3.UV light waves come from sunlight

4.x ray waves used at the doctors office

5. infrared waves are in remote controls when sending signals.

I don't know if I can think of another 5 right now. but I hope this helps.

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3 years ago

A charge of 6.7 x 10 coulombs is located at a point where its potential energy is 5.6 x 10-12 joules. What is the electric poten

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6.7 X 10 = 670

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714

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3 years ago

What is the function of the wire in

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I think the right answer is option B.

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4 years ago

A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a

Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial Velocity of Each object

$V_f$ = Final Velocity

Our values are given as

$m_1 = 2190Kg$

$v_1 =10.5m/s$

$m_2 = 3220kg$

$V_f = 4.74m/s$

Replacing we have that

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

$(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)$

$v_2 = 0.8224m/s$

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

8 0

4 years ago