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Karolina [17]
3 years ago
14

Is this right?? please help me. IT IS SOCIOLOGY!!

Physics
2 answers:
Westkost [7]3 years ago
8 0

Answer:

Yes, it is correct : )

Explanation:

Hope this helps!

ra1l [238]3 years ago
5 0

Answer:

yes, this is correct.

Explanation:

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laila [671]

Answer:

Neil Armstrong

Explanation:

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D) A tank with dimensions: 3m x 2m x 2m contains water upto its half
lorasvet [3.4K]

Answer:

P = 9800 [Pa]

Explanation:

In order to calculate the pressure at the bottom, we must use the following formula.

P = Ro*g*h

where:

P = pressure [Pa] (units of pascals)

Ro = density of the water = 1000 [kg/m³]

g = gravity acceleration = 9.8 [m/s²]

h = height = 1 [m] (because its half of the portion, the full height is 2 m)

P = 1000*9.8*1

P = 9800 [Pa]

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What factors affect the speed of a wave? Check all that apply.
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1. the energy of the wave, 2.the type of medium. 3.the amplitude of the wave. 4.the type of wave

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John is going to use a rope to pull his sister Laura across the ground in a sled through the snow. The rope makes an angle of 25
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The mass of Laura and the sled combined is 887.5 kg
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(a) An ideal gas initially at pressure p0 undergoes a free expansion until its volume is 3.80 times its initial volume. What the
trapecia [35]

Answer:

a)P/Po=0.263

b)γ=1.33 So gas is triatomic

c)\dfrac{KE_f}{KE_i}=1.56

Explanation:

a)

initial pressure = Po

Initial volume = Vo

Final volume = 3.8 Vo

Lets take final pressure is P

we know that for free expansion process

PV= Constant

Po x Vo = P x 3.8 Vo

P=0.263 Po

So

P/Po=0.263

b)

Now gas is compressed in adiabatic manner

Final pressure = 1.56 Po

                       =1.56 Po

We know that for adiabatic process

P_1V_1^{\gamma}=P_2V_2^{\gamma}

\dfrac{V_2}{V_1}=\left(\dfrac{P_1}{P_2}\right)^{\dfrac{1}{\gamma}}

0.263P_o(3.8V_o)^{\gamma}=1.56P_o\times V_o^{\gamma}

γ=1.33 So gas is triatomic

c)

We know that average kinetic energy given as

KE=\dfrac{3}{2}KT

\dfrac{KE_f}{KE_i}=\dfrac{T_f}{T_i}\

\dfrac{KE_f}{KE_i}=\dfrac{P_fV_f}{P_iV_i}

\dfrac{KE_f}{KE_i}=\dfrac{1.56P_oV_o}{P_oV_o}

\dfrac{KE_f}{KE_i}=1.56

3 0
3 years ago
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