Answer:
The magnitude of the displacement is 6.00 m.
Explanation:
Given that,
Radius = 3.00 m
Displacement :
The displacement is the shortest distance between initial and final points,
We need to calculate the magnitude of the displacement
Using formula of displacement
Put the value into the formula
Hence, The magnitude of the displacement is 6.00 m.
Ohm's law states that V=IR, where V=voltage, I=current(amps), and R=resistance (in Ohms).
Plugging the values into the above equation yields a resistance in the light bulb of 9.8 ohms
Explanation:
Area of square = 25^2 = 625 cm^2 or = 0.0625 m^2
number of turns = 100
Solenoid resistance = 10 ohms
now we know , Φ = B.A
where , Φ = magnetic flux, B= magnetic field strength, and A = area.
Φ = 10 × 0.0625 = 0.625 W
induced emf ε = dΦ/dt = d(BA)/dt =0
This is because both B and A are constants.
⇒ Induced current is also zero.
Replacing square by a circle will not change situation as the value of B and A will remain constant with time hence, no emf induced, so no current induced.
The question appears to be incomplete.
I assume that we are to find the coefficient of static friction, μ, between the desk and the book.
Refer to the diagram shown below.
m = the mass of the book
mg = the weight of the book (g = acceleration due to gravity)
N = the normal reaction, which is equal to
N = mg cos(12°)
R = the frictional force that opposes the sliding down of the book. It is
R = μN = μmg cos(12°)
F = the component of the weight acting down the incline. It is
F = mg sin(12°)
Because the book is in static equilibrium (by not sliding down the plane), therefore
F = R
mg sin(12°) = μmg cos(12°)
Therefore, the static coefficient of friction is
μ = tan(12) = 0.213
Answer: μ = 0.21 (nearest tenth)
The weight is the force of gravity acting on the object. So assuming it’s on earth, 12(9.81) also, F(weight in Newtons)=mass( in kg)acceleration (due to gravity)
