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2 years ago

Brainliest if correct

Mathematics

1 answer:

bulgar [2K]2 years ago

8 0

Answer:

$0.50/cm

Step-by-step explanation:

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(a) A shipment of 120 fasteners that contains 4 defective fasteners was sent to a manufacturing plant. The quality-control manag

denis-greek [22]

Answer:

a) Probability that exactly 1 fastener is defective, P(X = 1) = 0.144

b) Confidence interval for mean price, $CI = [4.1058, 4.1202]$

Step-by-step explanation:

a) Total number of fasteners = 120

Number of defective fasteners = 4

Probability of selecting a defective fastener, p = 4/120

p = 0.033

Probability of selecting an undefective fastener, q = 1 - p

q = 1 - 0.033

q = 0.967

5 fasteners were randomly selected, n =5

Probability that exactly one fastener is defective:

$P(X =r) = (nCr) p^r q^{n-r}\\P(X =1) = (5C1) 0.033^1 0.967^{5-1}\\P(X =1) = 0.144$

b) Number of gasoline outlets sampled, n = 900

Average gasoline price, $\bar{x} = 4.113$

Standard deviation, $\sigma = 0.11$

Confidence Level, CL = 95% = 0.95

Significance level, $\alpha = 1 - 0.95 = 0.05$

$\alpha/2 = 0.05/2 = 0.025$

From the standard normal table, $z_{\alpha/2} = z_{0.025} = 1.96$

error margin can be calculated as follows:

$e_{margin} = z_{\alpha/2} * \frac{\sigma}{\sqrt{n} } \\e_{margin} = 1.96 * \frac{0.11}{\sqrt{900} }\\e_{margin} = 0.0072$

The confidence interval will be given as:

$CI = \bar{x} \pm e_{margin} \\CI = 4.113 \pm 0.0072\\CI = [(4.113-0.0072), (4.113+0.0072)]\\CI = [4.1058, 4.1202]$

7 0

3 years ago

Please help I'll give brainliest if answer is right

Hatshy [7]

Answer:

The area is about 96.06 or 96.1

Step-by-step explanation:

I tried my best to solve it, I'm sorry if it's wrong.

6 0

2 years ago

Help please!!!!!!!!!!!!

Tpy6a [65]

Answer:

no solution

Step-by-step explanation:

if you plug in y=8-3x to 5y,

5(8-3x) the x's cancel out

40=20

^no real solution

3 0

3 years ago

How many different 11-letter arrangements can be made using the letters in the word Firecracker?

zhenek [66]

Answer:

Total number of arrangements = 1,663,200

Step-by-step explanation:

Given:

11 - letter

FIRECRACKER

F = 1

I = 1

R = 3

E = 2

C = 2

A =1

K = 1

Find:

Total number of arrangements = ?

Computation:

Note: Repeated letter will be avoid.

$Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2}\\\\Number\ of\ arrangements = \frac{!11}{!3 \times !2 \times !2} \\\\Number\ of\ arrangements = \frac{11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3}{3 \times 2 \times 2 } \\\\Number\ of\ arrangements = 1,663,200$

Total number of arrangements = 1,663,200

6 0

3 years ago

1) What percentage of 48 is 62?

dybincka [34]

Answer:

77.42

Step-by-step explanation:

48/62=77.42

3 0

3 years ago