B. from 52 moles of nitric acid, how many moles of silver nitrate will be produced?
1 answer:
Answer:
39 mol AgNO3
Explanation:
We have the equation 4HNO3 + 3Ag -----> 3AgNO3 + NO + 2H2O
We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )
We can calculate this by using mole ratio as well as dimensional analysis.
The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.
Using this we can create a table: The table is attached.
Breakdown of the table.
The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.
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Answer:
Choose the least electronegative atom other than H.
Explanation:
A Lewis structure consists of <em>terminal atoms</em> and one or more <em>central atoms</em>.
H can be <em>only a terminal atom</em> because it can form only one bond.
So the central atom must be either C or O.
The central atom is the less electronegative atom: C.
So, start the Lewis structure with a central C atom.
Then attach an O atom to get C-O.
Finally, attach the H atoms.
The condensed formula often gives you a clue where they go.
The formula CH₃OH implies that there are 3 H atoms on C and one on O.
The connectivity of the atoms is then as in the diagram below.
Answer:
a) 0,014 min⁻¹
b) 1452 seconds.
c) 0,02156 M
d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction
Explanation:
a) For a first order reaction the half-life is:
<em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹
b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.
As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds
c) In the same way, 11072 years are 4 half-life for this reaction, thus:
0,345M/2⁴ = 0,02156 M
d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.
By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction
I hope it helps!