3 years ago

Balance the equation Li +CO2+H2O—LiHCO3+H2

Chemistry

1 answer:

denpristay [2]3 years ago

5 0

Answer:2 Li+CO2+H2O=LiHCO3+H2

Explanation:

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A beaker contains 500 ml of 2.40M KNO3 the beaker is left uncovered so that all of the water evaporates. What mass of KNO3 cryst

telo118 [61]

Answer:

242.4 g

Explanation:

RAM of KNO3=39+14+(16×3)=101

Mass=morality×RAM

101*2.4=242.4

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2 years ago

CH4(g)+O2(g)→CO2(g)+H2O(g). What mass of water is produced from the complete combustion of 5.00×10−3 g of methane?

bixtya [17]

Answer:

1gram of water

Explanation:

First balance the equation

Ch4+2O2>CO2+2H2O

Ratio is 1:2

500×10-3what about 2?

500×10-3×2=1g

1g of water

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3 years ago

Examples of noble gases

LekaFEV [45]

Natural gas, desolate

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3 years ago

A gas occupies a volume of 1.00 L at 25.0°C. What volume will the gas occupy at 1.00 x10^2 °C?

Leno4ka [110]

Answer : The volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=1.00L\\T_1=25.0^oC=(25.0+273)K=298K\\V_2=?\\T_2=1.00\times 10^2^oC=((1.00\times 10^2)+273)K=373K$

Putting values in above equation, we get:

$\frac{1.00L}{298K}=\frac{V_2}{373K}\\\\V_2=1.25L$

Therefore, the volume of gas occupy at $1.00\times 10^2^oC$ is, 1.25 L

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3 years ago

Which of the following describes an ionic bond?

nydimaria [60]

C because it is and I know

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2 years ago