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harkovskaia [24]
3 years ago
8

Balance the equation Li +CO2+H2O—LiHCO3+H2

Chemistry
1 answer:
denpristay [2]3 years ago
5 0

Answer:2 Li+CO2+H2O=LiHCO3+H2

Explanation:

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How many chemicals in tobacco products have been proven to cause cancer?
baherus [9]

The answer is: 60.

Tobacco products are made up of thousands of chemicals, including at least 60 known to cause cancer (carcinogens).

Some of carcinogens chemicals are: acetaldehyde, arsenic, radioactive elements (for example polonium-210), nitrosamines, nickel, benzene, polycyclic aromatic hydrocarbons, vinyl chloride.

Smoking tobacco causes at least 15 different types of cancer. For example: mouth, pharynx, larynx, oesophagus, liver, pancreas, stomach, kidney cancer.

8 0
3 years ago
The normal boiling point of ethanol is 78.4 °C and 101.3 KPa. The heat of vaporization for ethanol is 42.32 kJ/mol. Determine th
Mandarinka [93]

Answer:

6.1×10^4Pa or 61KPa

Explanation:

The Clausius-Clapeyron equation is used to estimate the vapour pressure at different temperature, once the enthalpy of vaporization and the vapor pressure at another temperature is given in the question. The detailed solution is shown in the image attached. The temperatures were converted to kelvin and the energy value was converted from kilojoule to joule since the value of the gas constant was given in unit of joule per mole per kelvin. The fact that lnx=2.303logx was also applied in the solution.

7 0
3 years ago
Read 2 more answers
Tartaric acid, C4H6O6, has the first ionization constant with the value: Ka1 = 9.20 × 10-4. Calculate the value of pKb for the c
nirvana33 [79]

Answer:

pKb = 10.96

Explanation:

Tartaric acid is a dyprotic acid. It reacts to water like this:

H₂Tart  +  H₂O  ⇄  H₃O⁺   +  HTart⁻         Ka1

HTart⁻  +  H₂O  ⇄  H₃O⁺   +  Tart⁻²           Ka2

When we anaylse the base, we have

Tart⁻²   +  H₂O  ⇄  OH⁻  +  HTart⁻       Kb1

HTart⁻  +  H₂O  ⇄  OH⁻  +    H₂Tart          Kb2

Remember that Ka1 . Kb2  = Kw, plus pKa1 + pKb2 = 14

Kb2 = Kw / Ka1  →   1×10⁻¹⁴ / 9.20×10⁻⁴  = 1.08×10⁻¹¹

so pKb = - log Kb2   → - log 1.08×10⁻¹¹ = 10.96  

7 0
3 years ago
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Please help!!<br><br>Show the electronic configuration of magnesium atom​.
Galina-37 [17]

Explanation:

Magnesium has atomic number 12. It will be distributed in K, L, M shell in the following way:

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L shell can accommodate a maximum of 8 electrons and

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3 0
2 years ago
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What is the amount of moles for 12.0 g Ar?
Digiron [165]

if i am correct it shall be 12. because i am thinking, 1 mole = 1 ar.

8 0
3 years ago
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