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const2013 [10]
4 years ago
5

Describes changes in energy during a chemical reaction?

Chemistry
1 answer:
zysi [14]4 years ago
3 0

Answer:

Yes

Explanation:

Chemical reactions often involve changes in energy due to the breaking and formation of bonds. Reactions in which energy is released are exothermic reactions, while those that take in heat energy are endothermic.

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What are the gas laws? (Include Boyle's law, charles's law, gay lussac's law, an avogadro's law) Could someone please summarize
Rina8888 [55]

Answer:

Boyle's Law: When the pressure of a gas increases, the volume of the gas will decrease as long as the temperature and amount of gas are constant.

So basically pressure is inversely proportional to Volume, when one increases, the other decreases, vice versa.

Equation: P_{1} V_{1} = P_{2} V_{2}

Charles Law: When the temperature of a gas increases, the volume of a gas will also increase if the pressure and amount of gas are constant.

So basically Temperature and volume are directly proportional.

Equation: \frac{V_{1}}{T_{1}} = \frac{V_{2} }{T_{2} }

Gay Lussac's Law: When the temperature of a gas increases, the pressure of a gas also increases when volume and the amount of gas remain constant.

Basically, Temperature and Pressure are directly proportional.

Equation: \frac{P_{1}}{T_{1}} = \frac{P_{2} }{T_{2} }

Avogadro's Law: The most intuitive gas law. When you increase the amount of gas, the volume will also increase.

Meaning the moles (amount of gas) is directly proportional to volume.

Equation: \frac{V_{1} }{n_{1} } = \frac{V_{2} }{n_{2} } (n stands for moles)

There is a combined gas law and ideal gas law but those are just the gas laws mentioned above but combined together. These should be everything.

8 0
2 years ago
Read 2 more answers
How do you use nonmetal in a sentence?
skad [1K]
Here Is A Sentence You Could Possibly Use:

"Hydrogen and Nitrogen are two examples of non-metals."

(You can replace the two given elements with whatever two non-metallic elements you like.)

Hope This Helps!

BTW, You May Want A Second Opinion Just In Case! :)
7 0
3 years ago
A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL
snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43        

pH = 14 - pOH = 14 - 4.43 = 9.57

Now, the perchloric acid added will react with ammonia:

n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O    

n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles

Finally, we can calculate the pH of the resulting solution:

pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})  

pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98  

pH = 14 - 4.98 = 9.02

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

5 0
3 years ago
A que temperatura se produce el punto de fusión
Sholpan [36]

Answer:

<h2>32°F /0°C </h2>

Explanation:

At what temperature does the melting point occur?

32°F /0°C

(32°F − 32) × 5/9 = 0°C

At temperatures above 32°F (0°C), pure water ice melts and changes state from a solid to a liquid (water); 32°F (0°C) is the melting point. For most substances, the melting and freezing points are about the same temperature.

Is Melting Point affected by temperature?

Melting point, the temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.

6 0
4 years ago
Lisa’s book measures 40 cm x 10 cm x 2 cm. What is the volume of her book
White raven [17]

\text{Hello there! :)}

\large\boxed{V = 800cm^{3} }

\text{Formula for the volume of a rectangular prism:}\\\\V = l  * w * h\\\\\text{In this instance:}\\\\l = 40 cm\\w = 20 cm\\h = 10cm\\\\\text{Use the formula to solve for the volume:}\\V = 40 * 10 * 2\\\\V = 800cm^{3}

3 0
4 years ago
Read 2 more answers
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