Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
Perpendicular to base
Step-by-step explanation:
The cut creates two rectangular prisms (each angle must be 90 degrees)
The cut is perpendicular to the base
Answer:
Its really simple look it up at some site
The expression for the number of painted turtles in the pond will be 1/3f - 10.
Let the number of bullfrogs be represented by f.
From the given information, the number of painted turtles in a pond is ten less than one-third of the number of frogs, the expression for this will be:
= (1/3 × f) - 10
= 1/3f - 10
Therefore, the expression for the number of painted turtles in the pond will be 1/3f - 10. This implies that we have to multiply the fraction by f and then subtract 10 from the value.
In conclusion, the correct option is 1/3f - 10.
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