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zepelin [54]
1 year ago
12

Simplify the expressions:

Mathematics
1 answer:
Blizzard [7]1 year ago
7 0

Answer:

a. (7x²+2) + (2x²+3)

= 9x² + 5

b. (5x + 2) + (8x + 3)

= 13x +5

c. (5x)(8x + 3)

= 40x² + 15x

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Work out 5/6 x 3/4<br>Give the answer as a fraction in its simplest form.​
wolverine [178]

Answer:

The answer is 5/8

Step-by-step explanation:

8 0
3 years ago
In a certain​ chemical, the ratio of zinc to copper is 3 to 16. A jar of the chemical contains 736 grams of copper. How many gra
evablogger [386]

The jar has 138 grams of zinc.

<u>Solution:</u>

Given that , In a certain chemical reaction, the ratio of zinc to copper is 3 to 16.  

A jar of the chemical contains 736 grams of copper.  

We have to find how many grams of zinc does it contain

Let "n" be the grams of zinc needed for 736 grams of copper  

Now, we know that,  

16 grams of copper ⇒ 3 grams of zinc

Then, 736 grams of copper ⇒ n grams of zinc

So, by criss cross multiplication,

n \times 16 = 3 \times 736

16n = 3 x 736

16n = 2208

n = 138

Hence, the jar has 138 grams of zinc.

5 0
3 years ago
Find two positive real numbers whose product is a maximum. the sum is 80
Eduardwww [97]
Let's say the numbers are "a" and "b"

thus \bf y=ab\qquad &#10;\begin{cases}&#10;a+b=80\\&#10;b=80-a&#10;\end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\&#10;-----------------------------\\\\&#10;\cfrac{dy}{da}=80-2a

set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum
4 0
3 years ago
Read 2 more answers
A car travels 24 km in 15 minutes. How far does it travel in 1 and a half hours
VladimirAG [237]

Answer:

144 km

Step-by-step explanation:

1 hour and a half hour = 90 minutes.

In 15 minutes a car travels 24 km

In 1 minute a car travels (24÷15) = 1.6 km

In 90 minutes a car travels (90×1.6)= 144 km

Ans.- 144 km

4 0
3 years ago
Question 1
yaroslaw [1]

Answer:

sorry but i need some points right now so just ignore this

Step-by-step explanation:

8 0
3 years ago
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