See https://web2.0calc.com/questions/need-help-now_10.
Answer:
square units.
Step-by-step explanation:
We have to use limits to find the area of the region bounded by the graph
, the x-axis, and the vertical lines x=0 and x=1.
So, the area will be
A = 
= ![[4x - \frac{x^{4}}{2} ]^{1} _{0}](https://tex.z-dn.net/?f=%5B4x%20-%20%5Cfrac%7Bx%5E%7B4%7D%7D%7B2%7D%20%5D%5E%7B1%7D%20_%7B0%7D)
= 
=
square units. (Answer)
Answer: The result is one half (
)
Step-by-step explanation:
We have the following expression:

Since both fractions have the same denominator, we can just add both numerators and keep the denominator:

Dividing numerator and denominator by
:
This is the result
Answer:
sides are of 16 in
Step-by-step explanation:
here's your solution
==> area of square = 256 in^2. [given]
==> side of square = 4x
==> area of square= side^2
==> 4x^2 = 256
==> 16x^2 = 256
==> x^2 = 256/16
==> x^2 = 16
==> x = √16
==> x = 4
==> x = 4
hence sides are of 16 in
Hope it helps