The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
<h3>How to analyze quadratic equations</h3>
In this question we have a graph of a <em>quadratic</em> equation translated to another place of a <em>Cartesian</em> plane, whose form coincides with the <em>vertex</em> form of the equation of the parabola, whose form is:
g(x) = C · (x - h)² - k (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
By direct comparison we notice that (h, k) = (5, 1) and C = 1. Now we proceed to check if the points (x, y) = (2, 10) and (x, y) = (8, 10) belong to the parabola.
x = 2
g(2) = (2 - 5)² + 1
g(2) = 10
x = 8
g(8) = (8 - 5)² + 1
g(8) = 10
The <em>quadratic</em> function g(x) = (x - 5)² + 1 passes through the points (2, 10) and (8, 10) and has a vertex at (5, 1).
To learn more on parabolae: brainly.com/question/21685473
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No he cannot bc 61 is an odd number
The answer to your question would be 150 (c)
Equation of the line in point slope form is y + 3 = -1/2(x - 7)
Step-by-step explanation:
- Step 1: Given slope of the line is -1/2 and passes through the point (x1, y1) = (7, -3). Equation in point slope form is y - y1 = m(x - x1)
⇒ y - (-3) = -1/2(x - 7)
⇒ y + 3 = -1/2(x - 7)
Answer:
480
Step-by-step explanation:
1200 times 0.4 equals 480
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