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USPshnik [31]
3 years ago
14

A sample of chlorine gas starting at 688 mm Hg is placed under a pressure of 994 mm Hg and reduced to a volume of 500.2 mL. What

was the initial volume, in mL, of the chlorine gas container if the process was performed at constant temperature?
Chemistry
1 answer:
Alisiya [41]3 years ago
8 0

(P1V1=nRT1)/(P2V2=nRT2)

Constant temperature → (P1V1)/(P2V2)

688 mm Hg → 0.905 atm

994 mm Hg → 1.30789 atm

500.2 mL → 0.5002 L

(P1V1)/(P2V2)

(0.905)V1/(1.30789)(0.5002)

V1 = 0.72288 L → 722.88 mL

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A 25.0 ml solution of .0600 M EDTA was added to a 57.0 ml sample containing an unknown concentration of V3+. All V3+ present for
Rom4ik [11]

Explanation:

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Therefore, we will calculate the moles of Ga^{3+} as follows.

   Moles of Ga^{3+} solution = molarity × volume (L)

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                              = 0.000616 moles

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Also, the initial moles of EDTA will be calculated as follows.

     Total initial moles of EDTA = 0.0600 M × 0.025 L

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                = 0.00088 moles

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Now, we will calculate the molarity of V^{3+} as follows.

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olga55 [171]
The formula of aspartame is <span>C14H18N2O5.
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