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3 years ago

6

Based on your graph in the Periodic Trends Lab, what is the relationship between atomic radius and ionization energy ?

1 answer:

maxonik [38]3 years ago

6 0

As the atomic radius decreases, it becomes harder to remove an electron that is closer to a more positively charged nucleus. ... They experience a weaker attraction to the positive charge of the nucleus. Ionization energy increases from left to right in a period and decreases from top to bottom in a group.

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A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.0 gal tank

Usimov [2.4K]

Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.

Since, 1 US gal=3.78 L

Volume of tank in L will be:

$V=13.0 gal(\frac{3.78 L}{1 gal})=49.14 L$

Also, 1 L=1000 mL

Thus,

$V=49.14 L(\frac{1000 mL}{1 L})=49140 mL$

Mass of gasoline can be calculated as follows:

m=d×V

Here, d is density and V is volume thus,

$m=0.737 g/mL\times 49140 mL=3.62\times 10^{4}g$

Therefore, mass of gasoline will be $3.62\times 10^{4}g$ .

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3 years ago

What often occurs at a transform plate boundary (like the San Andreas Fault in California)? *

Zarrin [17]

It’s earthquakes

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3 years ago

What is the volume of 25 g of ethyl alcohol with a density of 0.79 g/mL?

Verdich [7]

Answer:

31.64...

Explanation:

The formula is volume is equal to mass over density.

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3 years ago

For this heterogeneous system 2 A ( aq ) + 3 B ( g ) + C ( l ) − ⇀ ↽ − 2 D ( s ) + 3 E ( g ) the concentrations and pressures at

maw [93]

Answer:

$2.55*10^{11$

Explanation:

Equation for the heterogeneous system is given as:

$2A_{(aq)} + 3 B_{(g)} + C_{(l)}$ ⇄ $2D_{(s)}$ $+$ $3E_{(g)}$

The concentrations and pressures at equilibrium are:

$[A] = 9.68*10^{-2}M$

$P_B = 9.54*10^3Pa$

$[C]=14.64M$

$[D]=10.11M$

$P_E=9.56*10^4torr$

If we convert both pressure into bar; we have:

$P_B = 9.54*10^3Pa$

$P_B = (9.54*10^3)*\frac{1}{10^5} bar$

$P_B=9.54*10^{-2}bar$

$P_E=9.56*10^4torr$

1 torr = 0.001333 bar

$9.54*10^4 *0.001333 = 127.5 bar$

$K=\frac{[P_E]^3}{[A]^2[P_B]^3}$

$K=\frac{(127.5)^3}{(9.68*10^{-2})^2(9.54*10^{-2})^3}$

$K=2.55*10^{11$

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3 years ago

A substance that is present in a reaction but not used up in the reaction is called a _____.

aleksandrvk [35]

They are called spectator ions.

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