Newtons’ THIRD Law of Motion
1 answer:
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Answer:
0.206 mol H₂O₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
7.00 moles H₂O₂
<u>Step 2: Identify Conversions</u>
Molar Mass of H - 1.01 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of H₂O₂ - 2(1.01) + 2(16.00) = 34.02 g/mol
<u>Step 3: Convert</u>
<u /> = 0.205761 mol H₂O₂
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
0.205761 mol H₂O₂ ≈ 0.206 mol H₂O₂
Answer:
1-Fluoro-4-nitrobenzene
Step-by-step explanation:
Step 1. Identify the substituents on the ring,
The groups are <em>fluoro</em> and <em>nitro</em>. They have no priority as functional groups, so the base name is <em>benzene</em>.
Step 2. Identify their relative priorities.
F and NO₂ have no functional group priority, so we list them in alphabetical order. F has <em>alphabetical priority </em>over NO₂. The name becomes <em>fluoronitrobenzene</em>.
Step 3. Number the atoms of the ring.
The C atom bearing the F is <em>C1.</em> Count around the ring, and the NO₂ group is on <em>C4</em>.
Step 4. Name the compound.
Insert the locating numbers <em>immediately in front</em> of the substituents. Use <em>hyphens</em> to join letters to numbers.
The name becomes 1-fluoro-4-nitrobenzene.
