What is the solution to the system of equations below?
1 answer:
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Answer:
3rd option.
Step-by-step explanation:
= 4
move 5 to the other side of the equation.
2|k| = 5(4)
2|k| = 20
move 2 to the other side of the equation.
|k| =
k = 10
Answer:
There is no solution to the problem
Step-by-step explanation:
In order to find the solutions to the problem you can write the situation in an algebraic form.
You have that a number is equal to twice a smaller number plus 3. This can be written as follow:
(1)
where x is the number and y is the smaller number
Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:
(2)
To find the solution you equal the equation (1) with (2), and you solve for y:
You obtain an inconsistency, hence, the situation of the problem does not have solution
Answer:
(x, y) = (-0.6, 0.8) or (1, 4)
Step-by-step explanation:
Use the second equation to substitute for y in the first.
(x -1)² +((2x +2) -2)² = 4
x -2x +1 + 4x² = 4 . . . . . . . eliminate parentheses
5x² -2x -3 = 0 . . . . . . . . . . subtract 4, collect terms
Now we can rearrange the middle term to ease factoring by grouping.
(5x² -5x) +(3x -3) = 0
5x(x -1) +3(x -1) = 0
(5x +3)(x -1) = 0
The values of x that make these factors zero are ...
x = -3/5, x = 1
The corresponding values of y are ...
y = 2(-3/5)+2 = 4/5 . . . . for x = -3/5
y = 2(1) +2 = 4 . . . . . . . . for x = 1
The solutions are: (x, y) = (-3/5, 4/5) or (1, 4).
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A graphing calculator verifies these solutions.
