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Alekssandra [29.7K]
2 years ago
10

Please help this question​

Mathematics
1 answer:
Dovator [93]2 years ago
7 0

Answer:

0

Step-by-step explanation:

let the vertices on either side of the 0 be A and B

then let the vertex opposite of O be C

First, angle ACB will be equal to 90° as it is the angle that lies on the same arc as the diameter. From there you can find angle y with angle A+ angle B+ Angle C=180°

then you can find the angle complementary to x with the same formula then you can subtract that angle with 90° to get x.

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What is the standard form equation of the line shown below?
jolli1 [7]
(-1,5)(2,4)
slope = (4 - 5) / (2 - (-1) = -1/3

y = mx + b
slope(m) = -1/3
use either of ur points (2,4)...x = 2 and y = 4
now sub and find b, the y int
4 = -1/3(2) + b
4 = -2/3 + b
4 + 2/3 = b
12/3 + 2/3 = b
14/3 = b

so ur equation is : y = -1/3x + 14/3....however, this is not ur answer because it is not in standard form.

y = -1/3x + 14/3
1/3x + y = 14/3....multiply both sides by 3
x + 3y = 14 <=== standard form
4 0
3 years ago
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0.249 in expanded form
nikklg [1K]
2.49×10^-1 is the answer
8 0
3 years ago
The area of a square is A and side is y. Express A in terms of y
kolezko [41]

Answer:

A = y^2

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5 0
3 years ago
What is 9 divided by 63
vlada-n [284]
Well 63 divide by 9 is 7 but 9 divide by 63 is .14
4 0
3 years ago
The Newport Crab Company marks the location of its crab pots with colored balloons. They mark every fourth pot with a red balloo
sasho [114]

Answer: There are 310 pots that have three different colored balloons attached.

Step-by-step explanation:

Since we have given that

Number of crab pots in the bay = 600

Part of red balloon = \dfrac{1}{4}

Part of blue balloon = \dfrac{1}{6}

Part of yellow balloon = \dfrac{1}{10}

So, Number of pots that have different colored balloons attached is given by

\dfrac{1}{4}\times 600+\dfrac{1}{6}\times 600+\dfrac{1}{10}\times 600\\\\=150+100+60\\\\=310

Hence, there are 310 pots that have three different colored balloons attached.

8 0
3 years ago
Read 2 more answers
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