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dezoksy [38]
3 years ago
13

DUE TOWMOROW HELP

Physics
1 answer:
eimsori [14]3 years ago
4 0

Answer:

a baby grasshopper is a nymph

Explanation:

hope this helps

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A solenoid of length 5.0 cm has a cross sectional area of 1.0 cm2 and has 300 uniformly spaced turns. The solenoid is wrapped in
OleMash [197]

The calculated mutual inductance is 8.544 x 10⁻⁵ H.

Two coils have a mutual inductance of 1 henry when emf of 1 volt is induced in coil 1 and when the current flowing through coil 2 is changing at the rate of one ampere per second.

Length of the solenoid= 5.0 cm

Area of cross-section=1.0 cm²

no of spaced turns=300 turns

turns of insulated wire=180 turns

Mutual inductance (M) = μ₀μr N1N2 A/ L

                                     =(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5

                                     =79.12 x 10⁻¹⁰ x 54000 / 5

                                     =8.544 x 10⁻⁵  H

hence, the mutual inductance is 8.544 x 10⁻⁵ H.

Learn more about Mutual inductance here-

brainly.com/question/14014588

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4 0
1 year ago
Photo used to help with the question is below!! Please answer! Will mark BRAINLIEST!
Sergeu [11.5K]
This statement is True, Because the phenomenon is called a Mirage!
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3 years ago
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Suppose you have a pendulum clock which keeps correct time on Earth(acceleration due to gravity = 1.6 m/s2). For ever hour inter
kaheart [24]

The moon clock is A) (9.8/1.6)h compared to 1 hour on Earth

Explanation:

The period of a simple pendulum is given by the equation

T=2\pi \sqrt{\frac{L}{g}}

where

L is the length of the pendulum

g is the acceleration of gravity

In this problem, we want to compare the period of the pendulum on Earth with its period on the Moon. The period of the pendulum on Earth is

T_e=2\pi \sqrt{\frac{L}{g_e}}

where

g_e = 9.8 m/s^2 is the acceleration of gravity on Earth

The period of the pendulum on the Moon is

T_m=2\pi \sqrt{\frac{L}{g_m}}

where

g_m = 1.6 m/s^2 is the acceleration of gravity on the Moon

Calculating the ratio of the period on the Moon to the period on the Earth, we find

\frac{T_m}{T_e}=\frac{g_e}{g_m}=\frac{9.8}{1.6}

Therefore, for every hour interval on Earth, the Moon clock will display a time of

A) (9.8/1.6)h

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3 years ago
Scientists observe a red shift when observing:
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The light we see is red-shifted when we observe a galaxy that's moving AWAY FROM US.
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Can someone check my answers please??
loris [4]
I checked them they are good.
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