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lesantik [10]
2 years ago
8

PLEASE HELP!!! ASAPPPPP

Mathematics
1 answer:
stiks02 [169]2 years ago
4 0
Answer = “$26 or more than $26”
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Show that the equation x^3+7x-4=0 has a solution between x=0 and x=1
Aleksandr [31]

Step-by-step explanation:

Using the Intermediate Value Theorem, the following is applied:

"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).

So here there must be a c such that

f(0) < f(c) < f(1)

Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists

Next, plug in the x values into the function

f(0)  =  - 4

f(1) =  {1}^{3}  + 7(1) - 4 = 4

Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)

3 0
2 years ago
PLEASE HELP:
Effectus [21]
The ratio of object to shadow is 3 ft object/1.5 ft shadow.
x ft object = 18.65 ft shadow
So you would multiply 18.65 by 1.5/3, which equals 9.325ft.
8 0
3 years ago
Read 2 more answers
Write an equation that represents the data in the table x 5,10,15,20 y 17,22,27,32
maks197457 [2]
They go up by 12
17-5=12
22-10=12
27-15=12
32-20=12

6 0
3 years ago
Find the error in the following sample of work, if one exists.
ch4aika [34]

Answer:

D. There is no mistake.

Step-by-step explanation:

The following lines show the process of factorization by using common factor.

<u>Line 1:</u>

In line 1, the equation is given and is completely fine.

y^{2}+8xy+2y+16x=0

The only thing missing was equate to zero, but the options below talk about correct factors only, therefore this can't be considered as a mistake and can be ignored completely.

<u>Line 2:</u>

In line 2, the terms are grouped, from which we can factor out common terms.

(y^{2}+8xy)+(2y+16x)=0

This is also fine.

<u>Line 3:</u>

In line 3, the common term y is taken out from group 1 and 2 from other group.

y(y+8x)+2(y+8x)=0

which is exactly what is given in line 3.

<u>Line 4:</u>

In line 4 the common factors can be seen and easily split into 2 factors.

(y+2)(y+8x)=0

which is exactly what is given in line 4.

Options:

A. The grouping is correct in line 2. So this option is does not hold.

B. Common factor was factored correctly from group 1. So this option does not hold.

C. Common factor was factored correctly from group 2. So this option does not hold.

D. There is no mistake. This is correct. Thus we choose this option as correct answer.

3 0
3 years ago
Harry’s team has won 13 less than 6 times as many games as it has lost. The team lost n games. Which expression could you use to
ad-work [718]

Answer:

A.

Step-by-step explanation:


7 0
3 years ago
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