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muminat
3 years ago
12

What is 1/5 of 35 ? HELPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics
2 answers:
Gala2k [10]3 years ago
4 0

Answer:

fraction, to work out the answer, we put the fraction 1/5 side by side with our new fraction, 35/1 so that we can multiply those two fractions.

That's right, all you need to do is convert the whole number to a fraction and then multiply the numerators and denominators. Let's take a look:

1 x 35

5 x 1

=

35

5

In this case, our new fraction can actually be simplified down further. To do that, we need to find the greatest common factor of both numbers.

Step-by-step explanation:

please mark me as brainlist please

Gre4nikov [31]3 years ago
3 0
The answer to this is $
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2×2×2+10-4÷4+3×3×3 can y'all please help this is due tomorrow
baherus [9]
Then you'll need to get started on it pretty soon.
Just take it slow and easy, and remember your order of operations (or PEMDAS).
First look through it and do any multiplications and divisions that you find.
Then do the additions and subtractions.
I just gave it a quick scan and I came up with 26. I dont know if it's correct.
Get to work. You can do this !
7 0
3 years ago
Please answer this correctly
MaRussiya [10]

Answer:

6 pizzas

Step-by-step explanation:

At least 10 and fewer than 20 makes it 10-19

So,

10-19 => 6 pizzas

6 pizzas have at least 10 pieces of pepperoni but fewer than 20 pieces of pepperoni.

5 0
4 years ago
AREA ADDITION AND SUBTRACTION URGENT?
Andrews [41]
The area of the yellow region is
48.29 ^{2}

8 0
3 years ago
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
2 years ago
How to do question 27
GenaCL600 [577]
1/(sin(90 + θ)cos(360 - θ))     -   tan²(-θ)

Note:

 sin(90 + θ) = cosθ        Cosine and Sine are complementary.

cos(360 - θ) = cosθ      Cosine positive in 4th quadrant.

tan(-θ) = -tanθ          Negative angle concept.


1/(sin(90 + θ)cos(360 - θ))     -   tan²(-θ) =  1/(cosθcosθ)     -   (-tanθ)²

                                                                 =  1/(cos²θ)     -       tan²θ

                                                                  =  (1/cosθ)²     -       tan²θ
Note: 1/cosθ = secθ

                                                                 =  (secθ)²     -       tan²θ

                                                                  =  sec²θ     -       tan²θ

                                                                  =  1


Note that    1+ tan²θ = sec²θ is a Trigonometric identity.

That means:  sec²θ     -       tan²θ = 1

Hope this explains it.
5 0
3 years ago
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