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Daniel [21]
4 years ago
15

I need some help with solving this problem 8d-5<6d+8

Mathematics
1 answer:
Lina20 [59]4 years ago
6 0

Answer: d < 13/2

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the greater than sign from both sides of the inequality :

                    8*d-5-(6*d+8)<0  

Step by step solution :

Step  1  :

1.1    Divide both sides by  2  

     d-(13/2)  < 0

Solve Basic Inequality :

1.2      Add  13/2  to both sides

            d < 13/2

Inequality Plot :

1.3      Inequality plot for

        2.000 d  - 13.000  <  0

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MA_775_DIABLO [31]

Answer:

(a) 750

(b) 1875

(c) 4875 or as a fracion 7/20

Step-by-step explanation:

4 0
3 years ago
What output is twice the sum of the input 3 and 4
Andreas93 [3]

Answer:

Required output = 14

Step-by-step explanation:

Sum of the input 3 and 4 = 3 + 4

Twice the sum means two times.

So, to find twice the sum of the input 3 and 4, we need to multiply the sum by 2.

2(3 + 4)

Perform the addition inside the parentheses.

2(3 + 4) = 2(7)

Now, multiply.

2(3 + 4) = 14

Hence, required output = 14

5 0
3 years ago
X + 3y = -9<br> 5x + 3y = 3
kap26 [50]

Answer:

X=3,y=-4

Step-by-step explanation:

The only change is x so you could figure it out that way or do this:

4x=12 by subtracting the secound equation by the first one (since both y's are being multiplied by the same thing you can do this to cancel them out while making one equation). and than figure out x=3 from there you input that into eithger equation to figure out y. Hope this helped!

7 0
3 years ago
Find a particular solution to<br> y′′+6y′+5y=18te^(2t).
Andreas93 [3]

Answer:

idk just google it :)

Step-by-step explanation:

1. google it

6 0
4 years ago
X3(2x2 + 3x) <br><br> a. 2x5 + 3x4 <br> b. 5x9 <br> c. 2x6 + 3x3 <br> d. 5x
Serhud [2]

Answer:

2x^5+3x^4

Step-by-step explanation:

x^3\left(2x^2+3x\right)

<u>Apply distributive law: </u>a\left(b+c\right)=ab+ac

  • x^3\left(2x^2+3x\right)=x^3\times \:2x^2+x^3\times \:3x
  • x^3\times \:2x^2+x^3\times \:3x
  • 2x^5+3x^4

<u>OAmalOHopeO</u>

5 0
3 years ago
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