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lyudmila [28]
2 years ago
14

80 POINTS -Pre Calc Questions

Mathematics
1 answer:
alexandr1967 [171]2 years ago
4 0

Answer:

x+y=30

2x+3y=80

multiplying equation one by -3 and add equation

-3x -3y=-90

2x +3y=80

2(10)+20(3)=80

80=80

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Y=x^2+5×+2 <br>y=×-1<br><br>pls​
docker41 [41]

Answer:

x=-1 \ or \ x=-3

Step-by-step explanation:

y = x^2 + 5x +2\\y = x-1\\\\

Equating both equations equal to each other:

x^2 + 5x+2 = x-1\\x^2+5x+2 -x +1 =0\\x^2 + 4x +3 = 0

Breaking the middle term:

x^2 + 4x +3 =0\\x^2 +3x + x +3 =0 \\x(x+3) +1 (x+3) = 0\\(x+1)(x+3)=0\\x+1 =0 \ or \ x+3 =0\\x=-1 \ or \ x=-3

5 0
3 years ago
Which of the inequalities matches the graph below?
WARRIOR [948]
A Picture would be better
4 0
3 years ago
Read 2 more answers
PLEASE HELP ME ASAP
Iteru [2.4K]

Answer:

part 1 = 49

part 2 = .25 seconds

Step-by-step explanation:

hope that can help!

3 0
3 years ago
In a class of 6, there are 2 students who forgot their lunch.
lukranit [14]

Answer:

1/8

Step-by-step explanation:

AB,AA,BB,BB,BB,BB,BB,BB,

*A IS THE students that forgot thier lunch

4 0
3 years ago
Tickets to a school production cost $5 for a student ticket and $10 for an adult ticket. A total of 67 tickets were purchased at
vazorg [7]

Answer:

Step-by-step explanation:

Keywords:

System of equations, variables, cost, tickets, adults, children.

For this case we must solve a system of equations with two variables represented by the tickets of students and adults of a school production.

We define the variables according to the given table:

a: Number of tickets sold to adults

c: Amount of tickets sold to children.

We then have the following system of equations:

A + c = 67

10a + 5c =440

From the first equation, we clear the value of the variable c:

C = 67 - a

Answer:

The value that could replace c in the table is:

C = 67 - a

Option C is the answer!

Hope it helped u if yes mark me BRAINLIEST!

Tysm! Plz

9 0
3 years ago
Read 2 more answers
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