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2 years ago

Which conversion requires division?

Mathematics

2 answers:

kirza4 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

since milimetres is a smaller unit than centimetre, we will divide. We use division to convert from smaller to bigger value

OLga [1]2 years ago

3 0

<h2>Hi there!</h2><h3>My name is $EternalFox-$ and I'll be helping you today!</h3>

Answer:

Option A.<em> millimeters -->centimeters</em>

Step-by-step explanation:

A millimeter is a unit in the metric system. It is used to represent the length of an object or a person. One millimeter is equal to 0.1 centimeters.

The symbol of millimeters is ‘mm’.

A centimeter is also a unit in the metric system. It is the unit of length and distance. The symbol of centimeters is cm.

<h3>To convert the value of length in mm to cm we have to divide the given value by 10.</h3>

An example would Be:-

10 mm = 10/10 = 1 cm

Hence, The Answer is option A. .<em> millimeters -->centimeters</em>

<em />

<em>-Have a splendid day!</em>

<em>-Good Luck with your Assignment!</em>

<em />

<em /> $EternalFox-$

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If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
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Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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