The volume of the oxygen gas at standard temperature is 41.36 liters.
The given parameters;
- <em>initial volume of oxygen, V₁ = 45 L</em>
- <em>temperature of oxygen, T₁ = 24 ⁰C = 297 K</em>
- <em>standard temperature, T₂ = 0 ⁰C = 273 K</em>
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The volume of the oxygen gas at standard temperature is determined by applying Charles law as shown below;
Thus, the volume of the oxygen gas at standard temperature is 41.36 L.
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Answer:
0.137 M NH3
Explanation:
First divide the mass of NH3 by the molar mass of NH3, and then divide by the volume to get molarity.
0.583 g / 17.031 g/mol = 0.0342 mol NH3
0.0342 mol NH3 / 0.250 L = 0.137 M NH3
i) 2KClO3 → 2KCL + 3O2
ii) HNO3 + NaHCO3 → H20 + CO2
iii) 2Na + 2H2O → 2NaOH + H2
Answer:
it is neutralized when they are combined