Bongeka purchased a new refrigerator and were expected to pay R1 684,00 five months ago and another R1 323,00 in eight months’ t
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The distance from friend's village to Lucas's house is 45 miles
Step-by-step explanation:
Lets assume the distance from Lucas home to friend's village is x miles
The time taken to cycle from Lucas home to friend's village is 3 hrs....t₁
The time taken if travelling at a 5 mph reduced speed is 1.5 hrs longer......t₂
t₂=4.5 hrs
t₁= 3 hrs
Speed for cycle in first instance, where t₁=3 hrs and distance is x miles
s₁=d/t = x/3 mph
Speed for cycle if travelling at a slower speed,
Time taken in the second instance when travelling at a slower speed
=
The distance from friend's village to Lucas's house is 45 miles
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Formula for speed:brainly.com/question/13664094
Keywords: cycle,home, village, travels,slower,longer
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Answer:
Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)
Step-by-step explanation:
n = 77
mean u = 26,226.2 bushels per acre
standard deviation s = 2,322.32
let E = true mean
let A = test statistic
Find 95% Confidence Interval
so
let A = (u - E) * ( / s) be the test statistic
we want P( average_l < A < average_u ) = 95%
look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test
average_l = -1.96 which corresponds to the 2.5%
average_u = 1.96
P( -1.96 < A < 1.96) = 95%
P( -1.96 < (u - E) * ( / s) < 1.96) = 95%
Solve for the true mean E ok
E < u + 1.96* (s / )
from -1.96 < (u - E) * ( / s)
E < 26,226.2 + 1.96*( 2,322.32 / )
E < 26,226.2 + 1.96*( 2,322.32 / )
E < 26,226.2 + 518.7197348105429466
upper bound is 26,744.9197
or
u - 1.96* (s / ) < E
26,226.2 - 518.7197348105429466 < E
25,707.48026519 < E
lower bound is 25,707.48026519
Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)