Solve the following system using elimination:
{7 x + 2 y = -19 | (equation 1)
{2 y - x = 21 | (equation 2)
Add 1/7 × (equation 1) to equation 2:
{7 x + 2 y = -19 | (equation 1)
{0 x+(16 y)/7 = 128/7 | (equation 2)
Multiply equation 2 by 7/16:
{7 x + 2 y = -19 | (equation 1)
{0 x+y = 8 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{7 x+0 y = -35 | (equation 1)
{0 x+y = 8 | (equation 2)
Divide equation 1 by 7:
{x+0 y = -5 | (equation 1)
{0 x+y = 8 | (equation 2)
Collect results:
Answer: {x = -5, y = 8
Looking at the angles of the triangles
N=S
M=R
O=T
so MON would be RTS
Yes because once you distribute the 3 in the first equation it turns it into 3h+12
The answer to your problem is -1x.
Answer:
Step-by-step explanation:
h(x)=44x+8-(30x+15)
=44x+8-30x-15
=44x-30x+8-15
=14x-7