Not sure this is entirely right but hey why not, right. <span> A planet orbiting a star orbits in an ellipse. Sometimes it's closer to the star and sometimes it's further. When it's closer to the star, the gravity on the planet from the star is stronger, so the planet speeds up. The area the planet sweeps over is equal because when it speeds up the length covered along the orbital path is greater, but it is also closer to the star, and that dimension is decreased. And because of our very intelligently designed and organized universe, these two factors cancel each other out perfectly </span>
<span>Hope I helped in some way!
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The acceleration of the first block (4 kg) is -9.8 m/s².
The given parameters:
- <em>Mass of the first block, m₁ = 4.0 kg</em>
- <em>Mass of the second block, m₂ = 2.0 kg</em>
The net force on the system of the two blocks is calculated as follows;
where;
- <em>T </em><em>is the tension in the connecting string due weight of the first block</em>
Thus, the acceleration of the first block (4 kg) is -9.8 m/s².
Learn more about net force on two connected blocks here: brainly.com/question/13539944
Answer:
<h2>line B</h2>
Explanation:
According to ohm's law V = IR where;
V i sthe supply voltage (in volts)
I = supply current (in amperes)
R = resistance (in ohms)
In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.
For line B, R = ΔV/ΔI
R = V₂-V₁/I₂-I₁
R = 14.0-4.0/7.0-2.0
R = 10.0/5.0
R = 2.0ohms
Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.
We can solve the problem by using Newton's second law of motion:
where
F is the net force applied to the object
m is the object's mass
a is the acceleration of the object
In this problem, the force applied to the car is F=1050 N, while the mass of the car is m=760 kg. Therefore, we can rearrange the equation and put these numbers in, in order to find the acceleration of the car:
The equation also tells us that the acceleration and the force have same directions: therefore, since the force exerted on the car is horizontal, the correct answer is
<span>
B) 1.4 m/s2 horizontally.</span>