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4 years ago

Only two electrons, with opposing spins, are allowed in each orbital is known as the

Physics

1 answer:

Sophie [7]4 years ago

3 0

Answer:

Only two electrons, with opposing spins, are allowed in each orbital is known as the Aufbau's principle.

Explanation:

Aufbau's principle states that at the ground state of atom the atomic orbits of lowest energy are first filled by the electrons followed by the atomic orbits of higher energy.

Example:

1s orbit is first filled by the electrons in the opposite spin followed by 2s. Thus, first 1s is filled with 2 electrons in the opposite spin before filling the 2s orbit.

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a man drags a 8.10 kg bag of mulch at a constant speed, applying a 29.5 N at 38°. what is the coefficient of friction?

lesantik [10]

Answer:

The coefficient of friction is 0.38.

Explanation:

The free body diagram is drawn below.

Let $f$ be frictional force acting in the backward direction as shown. Let the coefficient of friction be $\mu$ . Let $N$ be the normal reaction force acting on the bag.

Given:

Mass of the bag is, $m=8.10\textrm{ kg}$

Force acting at $\theta = 38$ ° is $F= 29.5\textrm{ N}$

Acceleration due to gravity is, $g=9.8\textrm{ }m/s^{2}$

The force F can be resolved into its components as $F_{x}=F \cos \theta$ and $F_{y}=F \sin \theta$

Therefore,

$F_{x}=29.5\cos(38)=23.25\textrm{ N}\\F_{y}=29.5\sin(38)=18.16\textrm{ N}$

Now, as there is no acceleration in vertical direction, therefore,

Sum of upward forces = Sum of downward forces

$N+F_{y}=mg\\N=mg-F_{y}=8.10\times 9.8-18.16\\N=79.38-18.16=61.22\textrm{ N}$

Now, as the bag is moving at a constant speed, so acceleration in the horizontal direction is also zero as acceleration is the rate of change of velocity.

Therefore, backward force = forward force.

$f=F_{x}\\f=23.25\textrm{ N}$

Now, frictional force is given as:

$f=\mu N\\\mu = \frac{f}{N}=\frac{23.25}{61.22}=0.38$

Therefore, the coefficient of friction is 0.38.

8 0

4 years ago

I want the answer pls

storchak [24]

Answer:

Percentage error = 2.63%

Explanation:

We are given the following

Original volume = 15.20mL

Student measurement = 14.8mL

Error = 15.20-14.80

Error = 0.40mL

percentage = Error/Original volume * 100

Percentage error = 0.4/15.20 * 100

Percentage error = 40/15.20

Percentage error = 2.63%

3 0

3 years ago

The area of the effort and load of the Piston of a hydrolic are 0.5 and 5m respectively. If a force of 100 Newton is applied on

Yanka [14]

Answer:

Explanation:

Using Pascal laws, which states that pressure are the input equals the pressure at the output.

Pressure is given as force/area

P1=P2

Then,

F1/A1=F2/A2

Cross multiply

F1A2=F2A1

Given that

Ae=0.5m² area of effort

Al=5m² area of load

Fl=? Force if load

Fe= 100N. Force of effort

Then applying pascal

Fl/Al=Fe/Ae

Fl/5=100/0.5

FL/5=200

Fl=200×5

Fl=1000N

The first safety load is 1000N

6 0

4 years ago

Which element has the same number of valence electrons as a krypton

AleksandrR [38]

Arsenic in period 4 group 5.

3 0

3 years ago

A jet plane is flying at a constant altitude. At time t1 = 0, it has components of velocity vx = 90 m/s, vy = 110 m/s. At time t

Vika [28.1K]

Answer:

a) See attachment.

b) a_avg = -8.66 i - 2.33 j

c) a = 195 degrees from + x-axis. |a_avg| = 8.97 m/s^2

Explanation:

Given:

- Initial Velocity V_i = (90 i + 110 j)

- Final velocity V_f = (-170 i + 40 j)

- t_i = 0

- t_f = 30.0 s

Find:

(a) Sketch the velocity vectors at t1 and t2. How do these two vectors differ?

(b) the components of the average acceleration

Solution:

- The change in velocity is given by:

Δ V = (V_f - V_i)

Δ V = ( -170 i - 90 i + 40 j - 110 j)

Δ V = (-260 i - 70 j)

- The change in time is given as:

Δ t = t_f - t_i = 30 - 0 = 30 s

-The average acceleration is:

a_avg = Δ V / Δ t

a_avg = (-260 i - 70 j) / 30

a_avg = -8.66 i - 2.33 j

- The magnitude of acceleration is:

|a_avg| = sqrt ( 8.66^2 + 2.33^2)

|a_avg| = sqrt (80.4245)

|a_avg| = 8.97 m/s^2

- The direction of acceleration is given by:

tan (Q) = a_y / a_x

Q = arctan(a_y / a_x)

Q = arctan(2.33 / 8.66)

Q = 15 degrees

Hence, 180 + 15 = a. a = 195 degrees from + x-axis.

8 0

3 years ago