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rewona [7]
2 years ago
10

What horizontal velocity should be given to a ball hanging on a 4.9 m long thread so that it slides to the height of the hanger

(do not take into account the force of air resistance)​
Physics
1 answer:
igomit [66]2 years ago
5 0

Answer:

13 u2 = 0 – (2 × –2 m/s2 × 6 m) = 24, u = 4.9 m

Explanation:

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In carbon dioxide (CO2), there are two oxygen atoms for each carbon atom. Each oxygen atom forms a double bond with carbon, so t
Anton [14]

ANSWER: d) 8

EXPLANATION: Two sets of two shared electrons (4 electrons total shared) = one set of a double covalent bond.

Therefore, 8 electrons total shared = two sets of double covalent bonds

5 0
2 years ago
When we look at a star
stiv31 [10]

I'm not really sure what specific answer they're looking for, but if it's an open-ended question, then let's think about it this way...

A light year, is the distance it takes for light to travel in a year. If an object is 50,000 light years away, then by the time the light travels to us, 50,000 years has passed. We are looking at a 50,000 year old image of that object. (ignoring gravity and spatial expansion fun stuffs)

4 0
3 years ago
What would happen if i put in different colors in the washer with hot water?
xxTIMURxx [149]
Probably it whould separate becase hot water departs things! Hope this helps
4 0
3 years ago
A rubbit gets down from a rump which its /\x=0.85m in 0.5s, The rubbit's mass is 2kg, what is the net Force?
Ira Lisetskai [31]

Answer: 13.6 N

Explanation:

The equation of motion for the rabbit is:

\Delta x=V_{ox}t+\frac{1}{2}a_{x}t^{2} (1)

Where:

\Delta x=0.85 m is the distance traveled by the rabbit

V_{ox}=0 m/s is the rabbit's initial velocity, assuming it started from rest

t=0.5 s is the time

a_{x} is the acceleration

Isolating a_{x}:

a_{x}=\frac{2 \Delta x}{t^{2}} (2)

a_{x}=\frac{2 (0.85 m)}{(0.5)^{2}} (3)

a_{x}=6.8 m/s^{2} (4)

On the other hand, the force F_{x} is given by:

F_{x}=m.a_{x} (5)

Where m=2 kg is the mass of the rabbit

Substituting (4) in (5):

F_{x}=(2 kg)(6.8 m/s^{2}) (6)

Finally:

F_{x}=13.6 N

6 0
3 years ago
Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)​
kirza4 [7]

−1
C
−1
and L
f
​
=3.5×10
5
Jkg
−1

Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f
​

Or 2×400×500=M×3.5×10
5

⟹ M=1.14kg
3 0
3 years ago
Read 2 more answers
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