46 POINTS will mark brainliest if correct
The radius of Mercury's orbit is r = 5.79 x 1010 m and its orbital period is T=88 days. What is the
magnitude of the orbital velocity for the planet around the sun, assuming a circular orbit?
A.7.21 x 103 m/s
B.8.45* 104 m/s
C.4.79 x 104 m/s
D.5.32 x 104 m/s
During a chemical reaction, atoms react with each other to form new products. hope this helps (:
Answer:
The substance is Mercury. It has 80 electrons revolving around nucleus and 80 protons inside nucleus.
Explanation:
Atomic number of atom represent the number of electrons and protons of the atom. Thus,
Number of electrons = number of protons = 80
The atom which has atomic number 80 in the periodic table is Mercury.
Answer:
2292W
Explanation:
Use the formula for energy first:
Where E = Energy || D = Distance || M = Mass.
Solve that equation:
E = 5 * 5500 ==> 27500J
To find power, divide energy per time:
27500J / 12s =~ 2292W
Did it in a rush, any problems message me
Answer:
answer in the picture provided.
Explanation:
