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ICE Princess25 [194]
3 years ago
10

The electrostatic force between two charges is originally F. Which expression represents the new electrostatic force between the

two charges if one charge doubles and the other one is divided by three?
• 1/6
• 3/2
• 2/3
• 6
Physics
1 answer:
Bad White [126]3 years ago
3 0

Answer: c)• 2/3

Explanation:

Lets say q1 and q2 are two charges with r distance far apart.

So electrostatic force

F = (k q1 q2) / r²

as k = Coulomb's constant

Now

q1' = 2q1

q2' = q2/3

Therefore the new electrostatic force

F' = (k q'1 q'2) / r²

F' = (k 2q1 q2) / 3r²

F' = 2/3 [(k q1 q2) / r²]

so F' = 2/3F

New electrostatic force  is 2/3F

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stich3 [128]

The final velocity before takeoff is 104.96 m / s.

<u>Explanation:</u>

The last velocity of a given object over some time defines the final velocity. The final velocity of the object is given by the product of acceleration and time and adding this product to the initial velocity.

To calculate the final velocity,

                          V = u + at

where v represents the final velocity,

           u represents the initial velocity,

           a represents the acceleration

            t represents the time taken.

                            v = 0 + (3.20)\times( 32.8)

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You drive for 5 hours at a speed of 70 km/hr. How far did you go?
zubka84 [21]

Answer:

350 miles

Explanation:

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A force has both______ and _______. Question 1 options: Speed and impact Magnitude and direction Motion and speed Direction and
Travka [436]

Answer:

magnitude

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Is Mars a gas planet or a rocky planet?
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Freight trains can produce only relatively small accelerations and decelerations. What is the final velocity, in meters per seco
Crank

Answer:

Explanation:

Initial velocity of train u = 3.4 m⁻¹ , Acceleration a = .065 ms⁻² ,

time t = 9.75 x 60 = 585 s.

v = u + at

= 3.4 + .065 x 585

= 41.425 m / s

distance travelled during the acceleration ( s )

s = ut + 1/2 at²

= 3.4 x 585 + .5 x .065 x 585²

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u = 41.425 m / s

v = u -at

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t = 66.28 s

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3 years ago
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