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2 years ago

Give a graph of velocity v, time does a horizontal line represent ?

Physics

1 answer:

riadik2000 [5.3K]2 years ago

8 0

The graph represents an object moving at constant velocity

Explanation:

A graph of velocity (v) versus time (t) of an object is generally used to give information about the motion of an object. In fact, from this graph, it is possible to infer several pieces of information:

The slope of the graph corresponds to the acceleration of the object. In fact, the acceleration of an object is defined as the rate of change of the velocity: $a=\frac{\Delta v}{\Delta t}$ , which also corresponds to the slope of the graph
The area under the curve between two times $t_1, t_2$ corresponds to the distance travelled by the object in that time interval.

In this problem, we have an object whose velocity-time graph corresponds to a horizontal line. We said that the slope of the graph corresponds to the acceleration of the object: since the slope of an horizontal line is zero, this means that the acceleration of this object is zero, and therefore the object is travelling at constant velocity.

Learn more about velocity:

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Aunt Matilda goes to a well and throws a penny straight down the well at 3.0 m/s. She hears a splash after 0.5 seconds. How deep

nevsk [136]

Answer : The correct option is (d) 2.73 m

Explanation :

By the 2nd equation of motion,

$s=ut+\frac{1}{2}at^2$

where,

s = distance or height = ?

u = initial velocity = 3.0 m/s

t = time = 0.5 s

a = acceleration due to gravity = $9.8m/s^2$

Now put all the given values in the above equation, we get:

$s=(3.0m/s)\times (0.5s)+\frac{1}{2}\times (9.8m/s^2)\times (0.5s)^2$

$s=2.73m$

Therefore, the correct option is (d) 2.73 m

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3 years ago

The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc

Law Incorporation [45]

The gravitational force between two objects is given by:
$F=G \frac{m_1 m_2}{r^2}$
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is $r=6940 km=6.94 \cdot 10^6 m$ , the gravitational force is $F=9.21 \cdot 10^4 N$ and the mass of the Earth is $m_1=5.98 \cdot 10^{24} kg$ , therefore we can rearrange the previous equation to find m2, the mass of the telescope:
$m_2 = \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg$

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3 years ago

Read 2 more answers

What is the impulse of a 3 kg object that starts from rest and moves to 20 m/s?

IrinaK [193]

Answer:

The impulse on the object is 60Ns.

Explanation:

Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.

F = m a

F = m( $\frac{v_{2} - v_{1} }{t}$ )

⇒ Ft = m( $v_{2}$ - $v_{1}$ )

where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, $v_{1}$ is its initialvelocity and $v_{2}$ is the final velocity of the object.

Therefore,

impulse = Ft = m( $v_{2}$ - $v_{1}$ )

From the question, m = 3kg, $v_{1}$ = 0m/s and $v_{2}$ = 20m/s.

So that,

Impulse = 3 (20 - 0)

= 3(20)

= 60Ns

The impulse on the object is 60Ns.

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2 years ago

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3 years ago

Give a graph of velocity v, time does a horizontal line represent ?​

Give a graph of velocity v, time does a horizontal line represent ?