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2 years ago

Give a graph of velocity v, time does a horizontal line represent ?

Physics

1 answer:

riadik2000 [5.3K]2 years ago

8 0

The graph represents an object moving at constant velocity

Explanation:

A graph of velocity (v) versus time (t) of an object is generally used to give information about the motion of an object. In fact, from this graph, it is possible to infer several pieces of information:

The slope of the graph corresponds to the acceleration of the object. In fact, the acceleration of an object is defined as the rate of change of the velocity: $a=\frac{\Delta v}{\Delta t}$ , which also corresponds to the slope of the graph
The area under the curve between two times $t_1, t_2$ corresponds to the distance travelled by the object in that time interval.

In this problem, we have an object whose velocity-time graph corresponds to a horizontal line. We said that the slope of the graph corresponds to the acceleration of the object: since the slope of an horizontal line is zero, this means that the acceleration of this object is zero, and therefore the object is travelling at constant velocity.

Learn more about velocity:

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A 2.45-kg frictionless block is attached to an ideal spring with force constant 355 N/m. Initially the spring is neither stretch

ANTONII [103]

Answer:

A. A = 0.913 m

B. amax = 132.24m/s^2

C. Fmax = 324.01N

Explanation:

When the block is moving at the equilibrium point , its velocity is maximum.

A. To find the amplitude of the motion you use the following formula for the maximum velocity:

$v_{max}=A\omega$ (1)

vmax = maximum velocity = 11.0 m/s

A: amplitude of the motion = ?

w: angular frequency = ?

Then, you have to calculate the angular frequency of the motion, by using the following formula:

$\omega=\sqrt{\frac{k}{m}}$ (2)

k: spring constant = 355 N/m

m: mass of the object = 2.54 kg

$\omega = \sqrt{\frac{355N/m}{2.45kg}}=12.03\frac{rad}{s}$

Next, you solve the equation (1) for A and replace the values of vmax and w:

$A=\frac{v}{\omega}=\frac{11.0m/s}{12.03rad/s}=0.913m$

The amplitude of the motion is 0.913m

B. The maximum acceleration of the block is given by:

$a_{max}=A\omega^2 = (0.913m)(12.03rad/s)^2=132.24\frac{m}{s^2}$

The maximum acceleration is 132.24 m/s^2

C. The maximum force is calculated by using the second Newton law and the maximum acceleration:

$F_{max}=ma_{max}=(2.45kg)(132.24m/s^2)=324.01N$

It is also possible to calculate the maximum force by using:

Fmax = k*A = (355N/m)(0.913m) = 324.01N

The maximum force exertedbu the spring on the object is 324.01 N

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2 years ago

Which is not a benefit of stretching? decreased flexibility improved tissue strength decreased chance of injury relief for tense

dmitriy555 [2]

Decreased flexibility

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2 years ago

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The normal boiling point of cyclohexane is 81.0 oC. What is the vapor pressure of cyclohexane at 81.0 oC?

Aloiza [94]

Answer:

The vapor pressure of cyclohexane at 81.0°C is 101325 Pa.

Explanation:

Given that,

Boiling point = 81.0°C

Atmospheric pressure :

Atmospheric pressure is the force per unit area exerted by the weight of the atmosphere.

The value of atmospheric pressure is

$P=101325\ Pa$

Vapor pressure :

Vapor pressure is equal to the atmospheric pressure.

Hence, The vapor pressure of cyclohexane at 81.0°C is 101325 Pa.

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2 years ago

A capacitor is charged to 8.0×10−4 C , then discharged by connecting a wire between the two plates. 35us after the discharge beg

Anettt [7]

Answer:

The average current is 19.567 A

Solution:

As per the question:

Charge, Q = $8.0\times 10^{- 4}\ C$

Time, t = $35\times 10^{- 6}\ s$

Now,

We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:

I = $\frac{Q}{t}$ (1)

Now, the charge that was transferred is 86 % of the original value.

Therefore,

We replace Q by 0.86Q in eqn (1):

I = $\frac{0.86\times 8.0\times 10^{- 4}}{35\times 10^{- 6}} = 19.657\ A$

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2 years ago

Newton's second

Andru [333]

Explanation:

The second law states that the greater the mass of an object, the more force it will take to accelerate the object. There is even an equation that says Force = mass x acceleration or F=ma. This also means that the harder you kick a ball the farther it will go.

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1 year ago

Give a graph of velocity v, time does a horizontal line represent ?​

Give a graph of velocity v, time does a horizontal line represent ?