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4 years ago

What are the factors of x2 − 81? (x + 9)(x − 9) (x − 9)(x − 9) (x + 3)(x − 27) Prime

Mathematics

2 answers:

Kaylis [27]4 years ago

6 0

X^2-81=x^2-9^2=(x+9)(x-9)

this is the answer

stiv31 [10]4 years ago

3 0

Answer: The correct option is (A) $(x+9)(x-9).$

Step-by-step explanation: We are given to select the factors of the following quadratic expression :

$E=x^2-81~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be using the following factorization formula :

$a^2-b^2=(a+b)(a-b).$

From (i), we have

$E\\\\=x^2-81\\\\=x^2-9^2\\\\=(x+9)(x-9).$

Thus, the factored form of the given expression is $(x+9)(x-9).$

Option (A) is CORRECT.

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0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

7 0

3 years ago

Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum product

kkurt [141]

Ummm if its multiply then its 1 and 6. is its addition then its 1 and 5 or 6 and 0. if its divide it would be 6 and 1. is its subtraction then it would be 7 and 1 or 6 and 0

3 0

4 years ago

A parabola has a vertex at the origin. The focus of the parabola is located at (–2,0).

12345 [234]

dam what Answer:

Step-by-step explanation:dom

no it’s not working

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=3x%20%5E%7B2%7D%20%2B%2010x%20%2B%208" id="TexFormula1" title="3x ^{2} + 10x + 8" alt="3x ^{2}

r-ruslan [8.4K]

if we're factoring you can use the AC method. A multiplied by C is 24. and 4x6 is 24.

(x+4)(x+6) is your answer

8 0

3 years ago

Please help, explain and be specifec please

Stolb23 [73]

Just think of it as normal subtraction. They both have the same denominators all you need to do is subtract. 11/12-7/12 is 4/12 if you simplify which just means to find the number that both 4 and 12 can go into equally the simplified answer would be 1/3. You just need to divide 4 by both the top and the bottom (numerator and denominator).

5 0

3 years ago