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vaieri [72.5K]
4 years ago
10

What are the factors of x2 − 81? (x + 9)(x − 9) (x − 9)(x − 9) (x + 3)(x − 27) Prime

Mathematics
2 answers:
Kaylis [27]4 years ago
6 0
X^2-81=x^2-9^2=(x+9)(x-9)

this is the answer 
stiv31 [10]4 years ago
3 0

Answer: The correct option is (A) (x+9)(x-9).

Step-by-step explanation:  We are given to select the factors of the following quadratic expression :

E=x^2-81~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following factorization formula :

a^2-b^2=(a+b)(a-b).

From (i), we have

E\\\\=x^2-81\\\\=x^2-9^2\\\\=(x+9)(x-9).

Thus, the factored form of the given expression is (x+9)(x-9).

Option (A) is CORRECT.

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Kylie explained that (negative 4 x + 9) squared will result in a difference of squares because (negative 4 x + 9) squared = (neg
Eva8 [605]

Given:

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(-4x+9)^2

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The correct statement for Kylie's explanation.

Solution:

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(-4x+9)^2

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