R + b = 146. Supposing that b=r+28,
r + (r+28) = 146, or 2r + 28 = 146.
Simplifying: 2r = 118. Then r = 59, and b = r+28 = 59+28 = 87 blue marbles
Answer:
43. I'm not really sure about this one but here's what I got:
The average height of a 4th grader is 58 inches. (Maybe that'll help) Also if it's by the number of kids in the class....I would assume that there are at most 33 kids in the class....I'm not sure what it's asking...sorry :(
46. There are 8 total marbles so if you were selecting a green marble the probability of getting a green marble would be 3/8. If there are 2 blue marbles then the probability would be 2/8 or 1/4
LINK: https://mathbitsnotebook.com/Geometry/Probability/PBIndependentDependent.html
48. In a deck of cards there are 26 black cards and 26 red cards. Number of event occurrences. Total number of trials. For example, if a dice is rolled 6000 times and the number '5' occurs 990 times, then the experimental probability that '5' shows up on the dice is 990/6000 = 0.165. That should help with this one
LINK:
https://explorable.com/experimental-probability
49. Since there are 6 sides and each side is a number 1-6, the probability of rolling a six is 1:6
50. This one is easy if you read the question right. There are no pink marbles....
I'm not that great with graphs
I hope this helped a little....some of the questions I didn't understand.
Answer:
- x = ±√3, and they are actual solutions
- x = 3, but it is an extraneous solution
Step-by-step explanation:
The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...
... x^2(6x -18) = (2x -6)(9)
... 6x^2(x -3) -18(x -3) = 0
...6(x -3)(x^2 -3) = 0
... x = 3, x = ±√3
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Alternatively, you can subtract the right side of the equation and collect terms to get ...
... x^2/(2(x -3)) - 9/(6(x -3)) = 0
... (1/2)(x^2 -3)/(x -3) = 0
Here, the solution will be values of x that make the numerator zero:
... x = ±√3
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So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.
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<em>Comment on the graph</em>
For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.
20° is the answer if you look on the other side
