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timurjin [86]
2 years ago
15

1. You are going to make one of these bags from a roll of cloth 1 meter wide. What

Mathematics
1 answer:
maks197457 [2]2 years ago
8 0

Answer:

1 cm

You are going to make one of these bags from a roll of cloth 1 meter wide. What

is the shortest length that you need to cut from the roll for the bag?

Step-by-step explanation:

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An arithmetic sequence with a third term of 8 and a constant difference of 5
Vanyuwa [196]

\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad  \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ \hrulefill\\[0.5em] a_3=8\\ n=3\\ d=5 \end{cases} \\\\\\ a_3=a_1+(3-1)5\implies 8=a_1+(2)5 \\\\\\ 8=a_1+10\implies -2=a_1 \\\\\\ \begin{cases} a_1=-2\\ d=5 \end{cases}\implies a_n=-2+(n-1)d

5 0
3 years ago
Marta simplified this expression.
adoni [48]

Answer:

  • Step 1

Step-by-step explanation:

<u>Marta made a mistake at step 1</u>

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  • 4 log₅ x = log₅ x⁴ - correct

<u>Property to be used </u>

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8 0
2 years ago
Help me with this please! :)
Ivenika [448]

Answer:

28

36

40

44

just do the number +1 and ×4

4 0
3 years ago
Read 2 more answers
Of the cars in the parking lot, 20% are silver. If 20% of the cars is 48 cars, what is the total number of cars in the parking l
astraxan [27]
To solve this, we are going to set up a simple rule of three: If 20% are 48 cars, 100% how many cars will be:
\frac{20----\ \textgreater \ 48}{100----x}
Now, we can express this as a proportion ans solve for x:
\frac{20}{100} = \frac{48}{x}
x= \frac{(100)(48)}{20}
x=240

We can conclude that there are 240 cars in the parking lot.
3 0
3 years ago
EXAMPLE 1 (a) Find the derivative of r(t) = (2 + t3)i + te−tj + sin(6t)k. (b) Find the unit tangent vector at the point t = 0. S
Tatiana [17]

The correct question is:

(a) Find the derivative of r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(b) Find the unit tangent vector at the point t = 0.

Answer:

The derivative of r(t) is 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is (j/2 + 3k)

Step-by-step explanation:

Given

r(t) = (2 + t³)i + te^(−t)j + sin(6t)k.

(a) To find the derivative of r(t), we differentiate r(t) with respect to t.

So, the derivative

r'(t) = 3t²i +[e^(-t) - te^(-t)]j + 6cos(6t)k

= 3t²i + (1 - t)e^(-t)j + 6cos(6t)k

(b) The unit tangent vector is obtained using the formula r'(0)/|r(0)|. r(0) is the value of r'(t) at t = 0, and |r(0)| is the modulus of r(0).

Now,

r'(0) = 3t²i + (1 - t)e^(-t)j + 6cos(6t)k; at t = 0

= 3(0)²i + (1 - 0)e^(0)j + 6cos(0)k

= j + 6k (Because cos(0) = 1)

r'(0) = j + 6k

r(0) = (2 + t³)i + te^(−t)j + sin(6t)k; at t = 0

= (2 + 0³)i + (0)e^(0)j + sin(0)k

= 2i (Because sin(0) = 0)

r(0) = 2i

Note: Suppose A = xi +yj +zk

|A| = √(x² + y² + z²).

So |r(0)| = √(2²) = 2

And finally, we can obtain the unit tangent vector

r'(0)/|r(0)| = (j + 6k)/2

= j/2 + 3k

8 0
3 years ago
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