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xenn [34]
2 years ago
7

Need help asp will give brainliest

Chemistry
1 answer:
Levart [38]2 years ago
7 0

Answer:

Explanation:

1: the sciencetific name of a giant squid is called Architeuthis

2: i dont know I think it says diet but: Giant squid mostly eat deep water fishes and other squids.
3: the range of a Giant squid can be found in oceans around the world at depths of at least 2,950 feet, but their exact  range is unknown.

4, characteristics,

1: it has two large fins attached to its mantle.

2: the giant squid have many unique features, such as their ability to produce 'ink' to distract and deter predators.  

3:


facts,

1: Their eyes are the largest eyes in the animal kingdom and are about 10 inches

2: Their big eyes help them to spy objects in dark depths where most other animals would see nothing

3: Until 2005, nobody had ever seen a giant squid that was alive.

4: According to the stories, an huge squid would wrap its arms around a whale, causing a terrible fight to start. 
5: Giant squid have small fins at the rear of their mantles used for locomotion. 


Human IMPACT

Not only can squids and octopuses sense sound, but as it turns out, these and other so-called cephalopods might be harmed by growing noise pollution in our oceans—from sources such as offshore drilling, ship motors, sonar use and pile driving.

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if

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}

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1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?
Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

  • <u><em>We have the following data:</em></u>

Vo (initial volume) = 1.00 L  

V (final volume) = 473 mL → 0.473 L  

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)  

P (final pressure) = ? (in atm)

  • <u><em>We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:</em></u>

P_0*V_0 = P*V

1*1 = P*0.473

1 = 0.473\:P

0.473\:P = 1

P = \dfrac{1}{0.473}

\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}

<u><em>Answer:  </em></u>

<u><em>The new pressure of the gas is 2.11 atm  </em></u>

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\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}

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