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shutvik [7]
2 years ago
5

A bag contains colored tiles 6 tiles are green 3 tiles are blue 3 tiles are red a tile will be randomly selected from the bag. W

hat is the probability in decimal form that the tile selected will be green? record your answ. Be sure to use the coreect place value correct place value.​
Mathematics
2 answers:
baherus [9]2 years ago
7 0

Answer:

6/12 = 0.5

Step-by-step explanation:

you add all the other tiles plus the green and then you do the green divided by that number

vfiekz [6]2 years ago
7 0

Solution:

<u>Note that:</u>

Probability that the tile will be green: Green tiles/Total tiles

  • Green tiles/Total tiles
  • => 6/6 + 3 + 3
  • => 6/12 = 1/2 = 50/100 = 0.5

The probability (In decimal) of obtaining a green tile is 0.5.

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980,000 hl

Step-by-step explanation:

There are 980,000 milliliters in 9.8 hectoliters.

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What is √49/144 expressed in simplest form
Serga [27]

Answer:

49/144

Step-by-step explanation:

Find the GCD (or HCF) of numerator and denominator

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Divide both the numerator and denominator by the GCD

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3 years ago
The probability is 0.4 that a traffic fatality involves an intoxicated or​ alcohol-impaired driver or nonoccupant. In 7 traffic​
Luden [163]

Answer:

a.

P(X=3)=0.2903\\\\P(X \geq  3)=0.5801\\\\P(X\leq 3)0.7102

b.

P(2\leq x\leq 4 )=0.7451

c. mean=2.8

d . standard deviation=1.2961

Step-by-step explanation:

We determine that the accident rates follow a binomial distribution. The rate of success p=0.4 and sample n=7:

P(x)={n\choose x}p^x(1-p)^{n-x}

#the probability of exactly​ three;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X=3)={7\choose 3}0.4^3(0.6)^{4}\\\\=0.2903

#At least(more than 2)

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 3)=1-P(X\leq 2)\\\\=1-{7\choose 0}0.4^0(0.6)^{7}-{7\choose 1}0.4^1(0.6)^{6}-{7\choose 2}0.4^2(0.6)^{5}\\\\=1-0.0280-0.1306-0.2613\\\\=0.5801

#At most 3;

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X \leq 3)={7\choose 0}0.4^0(0.6)^{7}+{7\choose 1}0.4^1(0.6)^{6}+{7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}\\\\\\\=0.0280+0.1306+0.2613+0.2903\\\\=0.7102

b. Between 2 and 4:

Using the binomial expression, this probability is calculated as:

P(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(2\leq x\leq 4 )={7\choose 2}0.4^2(0.6)^{5}+{7\choose 3}0.4^3(0.6)^{4}+{7\choose 4}0.4^4(0.6)^{3}\\\\\\\\\=0.2613+0.2903+0.1935\\\\=0.7451

Hence,the probability of between 2 and four is 0.7451

c. From a above, we have the values of n=7 and p=0.4.

-We substitute this values in the formula below to calculate the mean:

-The mean of a binomial distribution is calculated as the product of the probability of success by the sample size, mean=np:

\mu=np, n=7, p=0.4\\\\\mu=7\times 0.4\\\\=2.8

Hence, the standard deviation of the sample is 2.8

d. From a above, we have the values of n=7 and p=0.4

--We substitute this values in the formula below to calculate the standard deviation

-The standard deviation a binomial distribution is given as:

\sigma={\sqrt {np(1-p)}\\\\=\sqrt{7\times 0.4\times 0.6}\\\\=1.2961

Hence, the standard deviation of the sample is 1.2961

4 0
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olga2289 [7]
Maybe that would be 200×3 if that helps you at all.
4 0
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