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guapka [62]
2 years ago
5

Write an equation of the line passing through the points (4,6) and (-2, - 18).

Mathematics
1 answer:
olga_2 [115]2 years ago
4 0

Answer:

y = 4x – 10

Step-by-step explanation:

slope formula: m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

point-slope formula: y-y_{1}=m\left(x-x_{1}\right)

  1. Use slope formula and plug in your numbers: m = \frac{-18-6}{-2-4 }
  2. Solve for slope m = 4
  3. Use the point-slope formula to solve for the equation: y-6=4\left(x-4\right)
  4. Solve and find equation: y=4x-10

Note: When given two points you only need to pick one for the point-slope formula! Best to choose the positive one so you don't have to deal with the negatives!

Hope this helps! Please give Brainliest!

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6x = -24 Solve for x.
Salsk061 [2.6K]

Answer:

-4

Step-by-step explanation:

divide -24 by 6

x= -4

6 0
2 years ago
Read 2 more answers
A 13 3/4 -inch candle burns down in 11 hours. If b represents how much of the candle, in inches, has burned away at any time giv
allochka39001 [22]

Answer:

5t = 4b

Step-by-step explanation:

Here, we want to write a proportional relationship for b in terms of t

From the question, b represent the amount of candle burned away in a given time t hours

From what we have initially, 13 3/4 burnt in 11 hours

So in 1 hour, the amount burnt will be;

55/4/11 = 5/4

5/4 inches of candle burnt in 1 hour

5/4 inches = b/t

So b inches burnt in t hours

5/4 = b/t

5t = 4b

7 0
3 years ago
5.5r - 8.35s when r = 12 and s = 4.
nataly862011 [7]

Answer:

32.6

Step-by-step explanation:

just do this

5.5(12)-8.35(4)

then solve

6 0
3 years ago
Which shows the following expression using positive exponents?
Hitman42 [59]

Answer:

1. option B is correct i.e., \frac{-3a^{7}b^3b^1}{15a^{2}}

2. option D is correct i.e., \frac{a^3b^4}{ab^2}.

3. option B is correct i.e.,  \frac{n^{10}}{16m^{6}}.

Step-by-step explanation:

1. Since the given equation is:

\frac{-3a^{-2}b^3}{15a^{-7}b^{-1}}

As we know that a^{-x}=\frac{1}{a^x}

So, the given equation can be represented as:

\frac{-3a^{7}b^3b^1}{15a^{2}}


2. Given equation is:

\frac{a^3b^{-2}}{ab^{-4}}

As we know that a^{-x}=\frac{1}{a^x}

so the given equation can be represented as:

\frac{a^3b^4}{ab^2}.


3.  Given equation is:

(\frac{4mn}{m^{-2}n^6})^{-2}

by using the properties a^{-x}=\frac{1}{a^x},

and a^x\times a^y=a^{x+y}

(\frac{4mn}{m^{-2}n^6})^{-2}

= (\frac{4n^1n^{-6}}{m^{-2}m^{-1}})^{-2}

= (\frac{4n^{1+(-6)}}{m^{-2+(-1)}})^{-2}

= (\frac{4n^{-5}}{m^{-3}})^{-2}

= \frac{4^{-2}n^{-5\times (-2)}}{m^{-3\times (-2)}}

= \frac{n^{10}}{16m^{6}}.

which is option B.

5 0
3 years ago
Read 2 more answers
According to the given information, segment uv is parallel to segment wz, while angles squ and vqt are vertical angles. angle vq
svp [43]

Angle vqt is congruent to Angle squ by the vertical angles theorem. because angles squ and wrs are corresponding angles, they are congruent according to the Corresponding angles theorem.

Option b is true.

Here,

Segment uv is parallel to segment wz,

Angles squ and vqt are vertical angles.

Angle vqt is congruent to Angle squ by the Vertical angles theorem.

What is corresponding angles?

Any pair of angles each of which is on the same side of one of two lines cut by a transversal and on the same side of the transversal.

Now,

Angle vqt is congruent to Angle squ by the vertical angles theorem.

When, two angles are corresponding angle then, Angle vqt is congruent to Angle squ by the Vertical angles theorem.

And, they are congruent according to the Corresponding angles theorem.

Hence, Segment uv is parallel to Segment wz, while Angles squ and vqt are Vertical angles. Angle vqt is congruent to Angle squ by the vertical angles theorem. Because angles squ and wrs are corresponding angles, they are congruent according to the corresponding angle theorem. finally, Angle vqt is congruent to Angle wrs by the transitive property of equality.

So, Option b is true.

Learn more about the corresponding angles visit:

brainly.com/question/22190474

#SPJ4

4 0
1 year ago
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