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Klio2033 [76]
3 years ago
10

2^x + 2^-x =5/2 pls I need d. ans​

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

x= 1, -1

Step-by-step explanation:

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Look at the question
ziro4ka [17]

Answer:

Step-by-step explanation:

The better buy is the one where you get more area of pizza per dollar (area/price).

Since the problem gives diameter, we assume the pizzas are circle-shaped.

Circle Area = pi x (radius)², and radius r = 1/2 of diameter d.

*************************************************************************************

Pizza 1: d = 8 and price is $10

r = 1/2 x d = 4

Area of Pizza 1 = πr² = π(4)² = 16π

*** area/price for Pizza 1 = 16π/$10 = 1.6π area per dollar

**********************************************************************************

Pizza 2: d = 14 and price is $16

r = 1/2 x d = 7

Area of Pizza 2 = πr² = π(7)² = 49π

*** area/price for Pizza 2 = 49π/16 = 3.0625π area per dollar

***********************************************************************************

Pizza 2 is the better buy, with more pizza per dollar.

3 0
3 years ago
The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82,
ozzi

Answer:

Population variance 579

Population standard deviation 24

Step-by-step explanation:

The average estimated hours a person in the United States spent playing video games per year from 2002 to 2012 were 71, 80, 82, 78, 80, 91, 107, 121, 125, 131, and 142.

The population variance is given by:

\sigma^2=\frac{\sum(x-\mu)^2}{n}

\mu=\frac{71+80+82+78+80+91+107+121+125+131+142}{11}

\mu=\frac{1108}{11}

This implies that:

\sigma^2=\frac{(71-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+(82-\frac{1108}{11})^2+(78-\frac{1108}{11})^2+(80-\frac{1108}{11})^2+...+(142-\frac{1108}{11})^2}{11}

\sigma^2=\frac{70006}{121} =579 to the nearest whole number

The population standard deviation is

\sigma=\frac{\sqrt{70006} }{11}=24 to the nearest whole number.

3 0
3 years ago
Read 2 more answers
A cat gave birth to 4 kittens. Three of the kittens had different masses between 147 and 159 kg and one kitten had a mass of 57k
Marizza181 [45]

Answer:

Both the mean and median will increase, but the mean will increase by more than the median.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
David considered moving even closer to his workplace. He claims that if he had done so, the percent of decrease would have been
krok68 [10]
This is completely wrong for logical and mathematical reasons, but for the sake of time I will go over the mathematical reason.

Because all percentages are out of 100, nothing can physically be over 100%, though it is used frequently in hyperbolic sentences and exaggerated statements.

Hope I helped and good luck! 
3 0
3 years ago
Read 2 more answers
Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?
evablogger [386]

Answer:

The equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Step-by-step explanation:

The given expression is \sqrt[3]{32x^8y^{10}}

To find the equivalent expression:

\sqrt[3]{32x^8y^{10}}=(32x^8y^{10})^{\frac{1}{3}}

We may write the above expression as below:

=(32^{\frac{1}{3}})((x^8)^{\frac{1}{3}})((y^{10})^{\frac{1}{3}})

=(2)((4)^{\frac{1}{3}})(x^6)\times (x^2)(x^{\frac{2}{3}})(y^3)(y^{\frac{1}{3}}) (using square root properties)

=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y}) (combining the like terms and doing multiplication )

=2x^2y^3\sqrt[3]{4x^2y}

Therefore \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

Therefore the equivalent expression to the given expression is \sqrt[3]{32x^8y^{10}}=2x^2y^3\sqrt[3]{4x^2y}

5 0
3 years ago
Read 2 more answers
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