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k0ka [10]
2 years ago
15

What is the unknown fraction

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
6 0

Answer: B. 8/100

      Let's give 5/10 a denominator of 100 since 58/100 does, so they have common denominators:

5/10 * 10 = 50/100

      Now, we can subtract 50/100 from 58/100 to find the unknown fraction:

58/100 - 50/100 = 8/100

      This gives us an answer of,

                   B. 8/100

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What is the inverse of x=4-4y+y^2
Zarrin [17]
To find invers
1. solve for y
2. replace y with xinverse

so

x=4-4y+y^2
reorder right side
x=y^2-4y+4
factor right side
x=(y-2)^2
squaer root both sides
+/-√x=y-2
add 2 to both sides
2+/-√x=y
switch x and y
2+/-√y=xinverse

xinverse=2+√y or 2-√y
subtract 4 from both sides






5 0
3 years ago
A golfer earned the following scores over several rounds of golf: −3, 2, 0, −1, 2, −4. Jamar says these numbers can all be descr
otez555 [7]

Answer:

Jamar is correct.

Step-by-step explanation:

The scores are as follows :

−3, 2, 0, −1, 2, −4.

These numbers include negative, positive and 0 as well. These numbers cannot written in a fractional form. It means they are integers.

Here, amar says these numbers can all be described as integers, while Sophia says they are whole numbers.

It would mean that Amar is correct. Sophia is incorrect because she told that the are whole numbers. Whole numbers are simply number like 0,1,2,3,4....

3 0
3 years ago
Please help asap!!!!
Sergeu [11.5K]
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3 years ago
In the given figure △ABC ≅△DEC. Which of the following relations can be proven using CPCTC ?
Serhud [2]

Option B:

\overline{A B}=\overline{D E}

Solution:

In the given figure \triangle A B C \cong \triangle D E C.

If two triangles are similar, then their corresponding sides and angles are equal.

By CPCTC, in \triangle A B C \ \text{and}\ \triangle D E C,

\overline{AB }=\overline{DE} – – – – (1)

\overline{B C}=\overline{EC} – – – – (2)

\overline{ CA}=\overline{CD} – – – – (3)

\angle ACB=\angle DCE  – – – – (4)

\angle ABC=\angle DEC  – – – – (5)

\angle BAC=\angle EDC  – – – – (6)

Option A: \overline{B C}=\overline{D C}

By CPCTC proved in equation (2) \overline{B C}=\overline{EC}.

Therefore \overline{B C}\neq \overline{D C}. Option A is false.

Option B: \overline{A B}=\overline{D E}

By CPCTC proved in equation (1) \overline{AB }=\overline{DE}.

Therefore Option B is true.

Option C: \angle A C B=\angle D E C

By CPCTC proved in equation (4) \angle ACB=\angle DCE.

Therefore \angle A C B\neq \angle D E C. Option C is false.

Option D: \angle A B C=\angle E D C

By CPCTC proved in equation (5) \angle ABC=\angle DEC.

Therefore \angle A B C\neq \angle E D C. Option D is false.

Hence Option B is the correct answer.

\Rightarrow\overline{A B}=\overline{D E}

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Milena was 9 years and 3 months old
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