Answer:
A sodium atom has one electron in the outer shell. A chlorine atom seven electrons in the outer shell. A sodium atom loses an electron to a chlorine atom. The sodium atom becomes a positive sodium ion.
<span>chemicals reacting are written on the left, what is formed is written on the right after the = sign
eg Copper + oxygen = copper oxide.
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Given, the density of water is 0.9975 g/ml. Density of water is mass of water per unit volume. Mass of 1 ml of water supposed to be 0.9975 g from density of water. So, mass of 10 ml of water is (0.9975 X 10) g= 9.975 g. From graduated cylinder, mass of 10 ml water is measured to be 9.955 g. So, error for mass of 10 ml water= (9.975-9.955)=0.02 g. Percentage of error for 10 ml water is
= 0.2. Error in the mass for the 10 ml of water is 0.2 %.
Answer:
0.294 M
Explanation:
The computation of the final molarity of acetate anion is shown below:-
Lead acetate = Pb(OAc)2
Lead acetate involves two acetate ion.
14.3 gm lead acetate = Mass ÷ Molar mass
= 14.3 g ÷ 325.29 g/mol
= 0.044 mole
Volume of solution = 300 ml.
then
Molarity of lead is
= 0.044 × 1,000 ÷ 300
= 0.147 M
Therefore the molarity of acetate anion is
= 2 × 0.147
= 0.294 M
CF4 is the compound that has polar bonds, but dipole moment of O. C-f bond is a polar bond which is covalent. It has dipole of 4 polar C.F bonds and results in the overall monopolar molecule.
CF4 it has no net dipole moment.