Answer:
300kg
Explanation: The question says about 30%, so I think it is 300kg
Answer:
<h2>Density = 1.67 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 50 g
volume = 30 mL
Substitute the values into the above formula and solve for the density
That's
Wr have the final answer as
<h3>Density = 1.67 g/mL</h3>
Hope this helps you
Answer:
E. Water Freezing
Explanation:
Entropy refers to the degree of disorderliness of a system.
A. Water Evaporating: There is an increase in entropy, this is because the phase change is from liquid to gas. Gas particles are more disordered than liquid.
B. Dry Ice sublimating: Sublimating refers to a phase change from solid to gas. This is an increase in entropy, this is because the gas particles are more disordered than solid particles
C. Water Boiling: The phase change is from liquid to gaseous state. There is an increase in entropy. Gas particles are more disordered than liquid.
D. Ice melting: The phase change is from solid to liquid state. There is an increase in entropy. Liquid particles are more disordered than that of solid.
E. Water Freezing: The phase change is from liquid to solid state. There is a decrease in entropy. solid particles are less disordered than those of liquid.
Answer:
See Explanation
Explanation:
Given that;
N/No = (1/2)^t/t1/2
Where;
No = amount of radioactive isotope originally present
N = A mount of radioactive isotope present at time t
t = time taken
t1/2 = half life
N/1000=(1/2)^3/6
N/1000=(1/2)^0.5
N = (1/2)^0.5 * 1000
N= 707 unstable nuclei
Since the value of the initial activity of the radioactive material was not given, the activity of the radioactive material after three months is given by;
Decay constant = 0.693/t1/2 = 0.693/6 months = 0.1155 month^-1
Hence;
A=Aoe^-kt
Where;
A = Activity after a time t
Ao = initial activity
k = decay constant
t = time taken
A = Aoe^-3 *0.1155
A=Aoe^-0.3465
7.86 is the pOH of water at this temperature of 100 degrees celsius.
Option E is the right answer.
Explanation:
Data given:
Kw = 51.3 x 
pOH = ?
we know that pure water is neutral and will have pH pf 7.
The equation for relation between Kw and H+ and OH- ion is given by:
Kw = [H+] [OH-}
here the concentration of H+ ion and OH- ion is equal
so, [H+]= [OH-]
Putting the values in the equation of Kw
pKw = -log[Kw]
pKw = -log [51.3 x ]
pKw = 12.28
since H+ ion OH ion concentration is equal the pH of water is half i.e. 6.14
Now, pOH is calculated by using the equation:
14 = pOH + pH
14- 6.14 = pOH
pOH = 7.86
