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8_murik_8 [283]
3 years ago
8

PLEASE HELP ME OUT!!

Chemistry
1 answer:
vesna_86 [32]3 years ago
7 0

Answer:

hydrogen

Explanation:

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Complete combustion of 2.0 metric tons of coal to gaseous carbon dioxide releases 6.6X10¹⁰ J of heat. Convert this energy to
Jobisdone [24]

6.6 × 10^{10} J = 6.2 × 10^{7} British thermal units

First of all, we should know that 1 British thermal unit = 1055 Joules.

From question, heat = 6.6 × 10^{10} J

1 BTU = 1055 J

6.6 × 10^{10} J = \frac{1}{1055} ×  6.6 × 10^{10} British thermal units

                   = 6.2 × 10^{7} British thermal units

1000 Joules = 1 kilojoule

A kilojoule is a unit of measure of energy, in the equal way that kilometers degree distance. meals energy used to be measured in energy  and some international locations still use those gadgets.

The power we get from foods and drinks is measured in kilojoules. that is the metric time period for calorie. Kilojoules and energy constitute the equal aspect. One calorie is ready four kilojoules.

Calorie a unit for measuring warmth same to the quantity of warmth required to elevate the temperature of one gram of water one diploma Celsius.

Learn more about kilojoules here :- brainly.com/question/490326

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4 0
1 year ago
What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?
Vsevolod [243]

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

7 0
3 years ago
Chemistry student needs of 55g acetone for an experiment. by consulting the crc handbook of chemistry and physics, the student d
sergeinik [125]

Answer:

             70.15 cm³

Solution:

Data Given;

                  Mass  =  55 g

                  Density  =  0.784 g.cm⁻³

Required:

                  Volume  =  ?

Formula Used:

                  Density  =  Mass ÷ Volume

Solving for Volume,

                  Volume  =  Mass ÷ Density

Putting values,

                  Volume  =  55 g ÷ 0.784 g.cm⁻³

                  Volume = 70.15 cm³

5 0
3 years ago
Pls can someone help me with this pls
GenaCL600 [577]

Answer:

not sure if this is the right way to answer this question but PbS is Phosphate-buffered saline (i think)

Explanation:

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