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2 years ago

Help????????????????

Mathematics

2 answers:

tester [92]2 years ago

5 0

Step-by-step explanation:

(12, -11) represents (x, y)

so 12 is x

-11 is y

now we need to do

x-9 and y+9

x-9=

12 - 9 = ???

y+9=

-11 + 9 = ???

then put into formate (x, y) as before

if you need more help comment and please put as brainiest

Bas_tet [7]2 years ago

4 0

Answer:

(3, -2)

Step-by-step explanation:

(x - 9, y + 9)

plug 12 for x, plug -11 for y

(12 - 9, -11 + 9)

(3, -2)

I hope this helps!

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you need to raise at least $400 in order to go on a field trip. you are selling magazines for $12 each. you have already raised

Kryger [21]

Answer:

44 magazines need to be sold

Step-by-step explanation:

Y=Mx+b

400=12x-124

524=12x

43.6667 or 43 (2/3)

round up since you cant sell 2/3 of a magazine

4 0

3 years ago

Read 2 more answers

The sum of series of 4+ 15 + 26 + ….. + 213

Gnom [1K]

Decompose the terms in the sum as

$4 + 15 + 26 + \cdots + 213 = 4 + (4 + 11) + (4 + 2\times11) + \cdots + (4 + 19\times11)$

so there are 20 terms in the sum. Then our sum simplifies to

$4 + 15 + 26 + \cdots + 213 = 4\times20 + (0+1+2+\cdots+19)\times11$

Now, if

$S = 1 + 2 + 3 + \cdots + 17 + 18 + 19$

we can reverse the order of terms to get the same sum,

$S = 19 + 18 + 17 + \cdots + 3 + 2 + 1$

so that doubling up the sum gives

$2S = (1 + 19) + (2 + 18) + \cdots + (18 + 2) + (19 + 1) = 19\times20 \implies S=19\times10=190$

So, our sum evaluates to

$4 + 15 + 26 + \cdots + 213 = 4\times20 + 190\times11 = \boxed{2170}$

5 0

2 years ago

I NEED HELP ASAP PLEASE

nataly862011 [7]

Answer: x = 9

Step-by-step explanation:

4 0

3 years ago

Factored form of 2x^2+x-3 must show work

frozen [14]

Answer:

(2x+3)(x - 1)

Step-by-step explanation:

Since there is no common number to factor by we must approach this problem differently:

Step 1:

Multiply leading coefficient (2) by the constant term (-3)

2 x -3 = -6

Step two:

Find two numbers that multiply to -6 but add to the middle coefficient (1).

You should find these numbers to be 3 and -2

Step 3:

Replace 1x in the equation with your found numbers

2x^2 - 2x + 3x - 3

Step 4:

Take out the greatest common factor from the first two numbers, and the last two numbers.

For 2x^2 - 2x the greatest common factor would be 2x

For 3x - 3 the greatest common factor would be 3.

Step 5:

Factor out the found common factors

2x(x-1) + 3(x-1)

The values inside the bracket should be the same.

Step 6:

Factor out (x-1)

(x - 1)(2x + 3)

Therefore the factored form is (2x + 3)(x - 1)

4 0

3 years ago

Help please will mark best answer

77julia77 [94]

I figured out the first question, the second one in lost on.

$\frac{(6-x)}{x^2+3x-28} / \frac{x^2-36}{x^2+5x-36}$

Factor both of the equations, numerator and denominator

$\frac{(6-x)}{(x+7)(x-4)}* \frac{(x+6)(x-6)}{(x+9)(x-4)}$

Cancel the like factors *excuse the zero im just showing you*

$\frac{(0)}{(x+7)} *\frac{(x+6)}{(x-9)}$

Combine frunctions

$\frac{(6+x)}{(x-9)(x+7)}$

x-9=0
x+7=0

Restrictions are 9 and -7

4 0

4 years ago