<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
B. Parallel
Step-by-step explanation:
Equation 1 simplified: y = 3x+7
Equation 2 simplified: y = -x/3-3
The slopes are completely different, ruling out the possibility of the lines being parallel.
But we also see the slopes of the equations are opposite and negative to each other. Making the lines perpendicular.
Natural numbers between 5002 and 5012 are 5003 5004 5011 there are nine in all
Answer:
Step-by-step explanation:
Combine like terms
8+7y+2x+4y+4
11y+2x+12
