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Pavel [41]
3 years ago
7

The system of equations has 2x-y=2(x+1) y=-2

Mathematics
1 answer:
sleet_krkn [62]3 years ago
3 0

Answer:

A.

Step-by-step explanation:

This equation has no solution.

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The relation R is shown in the table below.
Volgvan

Answer:

Domain: {-3, -1, 1}

Range: {-1, 2, 4, 5}

Step-by-step explanation:

8 0
3 years ago
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Angles A and B are complementary angles in a right triange. The value of cos(A) is 12/13. What is the value of Tan(A)
Orlov [11]
Using the pythagorean identity, we can find the value of sin(A)

cos^2(A) + sin^2(A) = 1
(12/13)^2 + sin^2(A) = 1
144/169 + sin^2(A) = 1
sin^2(A) = 1 - 144/169
sin^2(A) = 169/169 - 144/169
sin^2(A) = (169 - 144)/169
sin^2(A) = 25/169
sin(A) = sqrt(25/169)
sin(A) = 5/13

Which is then used to find tan(A)

tan(A) = sin(A)/cos(A)
tan(A) = (5/13) divided by (12/13)
tan(A) = (5/13)*(13/12)
tan(A) = (5*13)/(13*12)
tan(A) = 5/12

The final answer is 5/12

5 0
3 years ago
pleassssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssssseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeehelp
kifflom [539]
U kno how to simplify
3 0
3 years ago
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A manufacturer of nails claims that only 4% of its nails are defective. A random sample of 20 nails is selected, and it is found
irakobra [83]

Answer:

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

Step-by-step explanation:

A manufacturer of nails claims that only 4% of its nails are defective.

At the null hypothesis, we test if the proportion is of 4%, that is:

H_0: p = 0.04

At the alternative hypothesis, we test if the proportion is more than 4%, that is:

H_a: p > 0.04

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

4% is tested at the null hypothesis

This means that \mu = 0.04, \sigma = \sqrt{0.04*0.96}

A random sample of 20 nails is selected, and it is found that two of them, 10%, are defective.

This means that n = 20, X = 0.1

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.1 - 0.04}{\frac{\sqrt{0.04*0.96}}{\sqrt{20}}}

z = 1.37

P-value of the test and decision:

Considering an standard significance level of 0.05.

The p-value of the test is the probability of finding a sample proportion above 0.1, which is 1 subtracted by the p-value of z = 1.37.

Looking at the z-table, z = 1.37 has a p-value of 0.9147

1 - 0.9147 = 0.0853

The p-value of the test is 0.0853 > 0.05, which means that there is not enough evidence to reject the manufacturer's claim based on this observation.

7 0
3 years ago
Read 2 more answers
Simplify the ratio 24:135
kap26 [50]
The answer is 8:45. Enjoy!
5 0
4 years ago
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