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NNADVOKAT [17]
2 years ago
14

Just before midnight, the first musher, William “Wild Bill” Shannon, left Nenana. It was -50ºF. When he took his first break, it

was 12º colder. What was the temperature?
Mathematics
2 answers:
sashaice [31]2 years ago
8 0
Getting colder means there was temperature reduction
(ie the hotter the temperature the higher its value and the colder the temperature the lower its value)
Hence the temperature was
= -50 - 12
= -62 °F
Lubov Fominskaja [6]2 years ago
4 0

Answer:

-62°F

Step-by-step explanation:

it said it got colder so it got lower not higher

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128 inches
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Step-by-step explanation:

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3 years ago
You have the following coins in your pocket five quarters six dimes two nickels and 12 pennies what is the probability as a deci
irinina [24]

Answer: The probability of you drawing a dime is 0.24

Step-by-step explanation:

5 quarters, 6 dimes, 2 nickels, 12 pennies

5+6+2+12= 25

6/25= 0.24 or 24%

3 0
3 years ago
Read 2 more answers
Suppose that f(5) = 3, f '(5) = 6, g(5) = −5, and g'(5) = 2. Find the following values. (a) (fg)'(5) (b) f g '(5) (c) g f '(5)
baherus [9]

Answer: a) -24

              b) -\frac{36}{25}

              c) 4

Step-by-step explanation:

a) To determine the value of (fg)', use the product rule of derivative, i.e.:

(fg)'(x) = f'(x)g(x) + f(x)g'(x)

(fg)'(5) = f'(5)g(5) + f(5)g'(5)

(fg)'(5) = 6(-5) + 3(2)

(fg)'(5) = -24

b) The value is given by the use of the quotient rule of derivative:

(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}

(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}

(\frac{f}{g})'(5)=\frac{6(-5)-3(2)}{(-5)^{2}}

(\frac{f}{g})'(5)=\frac{-36}{25}

c) (\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}

(\frac{g}{f})'(5)=\frac{2(3)-(-5)(6)}{3^{2}}

(\frac{g}{f})'(5)=\frac{36}{9}

(\frac{g}{f})'(5)=4

7 0
3 years ago
A population of crawfish in a section of the Louisiana bayou increased from 900,000 to 1.2 million between 2010 and 2011. If the
slega [8]

Answer: 1,599,960

Step-by-step explanation:

Since the population of crawfish in a section of the Louisiana bayou increased from 900,000 to 1.2 million between 2010 and 2011. The percentage increase in population will be:

= (1.2 million - 900000) / 900000 × 100

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Since the population increases by the same percentage between 2011 and 2012, then the population in 2012 will be:

= (100% + 33.33%) × 1.2 million

= 133.33% × 1.2 million

= 1.3333 × 1.2 million

= 1,599,960

The population in 2012 is 1,599,960

5 0
3 years ago
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