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aliya0001 [1]
2 years ago
12

Determine the pressure change when a volume of gas at 760 mmHg is heated from 30.0 °C to 40.0 °C.

Chemistry
1 answer:
bekas [8.4K]2 years ago
5 0

Answer:

<u>253.33 mmHg</u>

Explanation:

According to Charles' Law,

P₁ / T₁ = P₂ / T₂

P₁T₂ = P₂T₁

P₂ = P₁T₂ / T₁

= 760 x 40 / 30

= 760 x 4/3

= 1013.33 mmHg

Change in Pressure

= 1013.33 - 760

= <u>253.33 mmHg</u>

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The average volume of a cotton ball is about 5.50 mL. If the mass of the cotton ball is 8.53 g, what is the density of cotton?
s344n2d4d5 [400]

Answer:

Explanation:

5.5 I believe.

6 0
3 years ago
Using the perodic table determine the number of protons for the element Li​
wolverine [178]
Answer is 3

because on the periodic table, the small number above every element is the number of protons
8 0
3 years ago
A gaseous mixture consisting of nitrogen, argon, and oxygen is in a 3.5-L vessel at 25C. Determine the number of moles of oxygen
Step2247 [10]

Answer:

Number of moles of oxygen = 0.037  mol

Explanation:

Given data:

Total pressure = 98.5 KPa

Partial pressure of nitrogen = 22.0 KPa

Partial pressure of argon = 50.0 KPa

Volume = 3.5 L

Temperature = 25°C (25+273= 298K)

Number of moles of oxygen = ?

Solution:

Total pressure = P(N₂) + P(O₂) + P(Ar)

98.5 KPa = 22.0 KPa +P(O₂) + 50.0 KPa

98.5 KPa = 72.0 KPa +P(O₂)

P(O₂)  = 98.5 KPa - 72.0 KPa

P(O₂)  = 26.5 KPa

KPa to atm:

26.5 KPa/ 101 = 0.262 atm

Number of moles of oxygen:

PV = nRT

n = PV/RT

n = 0.262 atm × 3.5 L / 0.0821 atm.L/mol.K  × 298 K

n = 0.917atm.L /24.47atm.L/ mol

n = 0.037  mol

6 0
3 years ago
What is the name of the molecule that is used to heat most of our buildings?<br><br> (Chemistry)
mario62 [17]

Answer:

Fluids (air/water) either as water vapour or oxygen and carbon dioxide.

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Heat transfer occurs through conduction, convection or radiation.

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Building materials have varying conductivity.

7 0
3 years ago
How many moles of water are there in 1.000 l at stp? assume the density of water is 1000 kg/m3?
EastWind [94]
Assume 1 liter = 1 kilogram of water = 1000 grams of water.

Part A)
MW of hydrogen is 1.008g/mol, and oxygen is 16.00g/mol.

Find the MW of water by
2*(1.008) + (16.00) = 18.016g/mol.

Convert 1000g H2O to moles :

(1000g H2O)*(1mol H2O / 18.016g H2O) = 55.51 mol

Part B)
Using the answer from part A and Avogadro's number:

(55.51mol)*(6.022*10^23) =

3.343*10^25 molecules.
Hope this is helpful
7 0
3 years ago
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