When burning sodium (Na) in oxygen (O2), you get sodium oxide (Na2O) and/or sodium peroxide (Na2O2). At high pressures, you can additionally get sodium superoxide (NaO2).
4 Na + O2 → 2 Na2O, and then partially 2 Na2O + O2 → 2 Na2O2.
Under normal conditions, approximately 20% of the mixture is Na2O2.
6 Na + 2 O2 → 2 Na2O + Na2O2
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Explanation:
The chemical formula of an ionic compound can be written by using the symbols of the respective cations and anions.
The overall charge on the molecule should be zero.
Hence, the total charge of cations=total charge of anions.
The symbols of the given molecules are shown below:
sodium chloride ---- NaCl
magnesium chloride ---
calcium oxide ---- CaO
lithium phosphide----
aluminum sulfide ----- 
calcium nitride---- 
Answer:
See explanation below
Explanation:
The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.
Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.
For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)
For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.
Sea level may rise as a result of the expansion of seawater and the melting of land-based ice due to a warming environment.
<h3>What is the sea level?</h3>
The sea level is the fundamental level for calculating height and depth on Earth. Since the ocean is one continuous body of water, its surface tends to seek a constant level. The sea surface is not actually level due to winds, currents, river discharges, fluctuations in gravity, and temperature.
<h3>Why is sea level important?</h3>
People are impacted by sea level changes through flooding, the inability of rivers to empty into the ocean due to the sea being too high, and the surge of seawater onto the land during storms. Our drinking water and the ability to cultivate crops could be harmed if sea water gets into farms and reservoirs.
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