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Juliette [100K]
3 years ago
5

What is the name of this molecule?

Chemistry
1 answer:
sveta [45]3 years ago
5 0

Answer:

The formula of the molecule given above can also be written as C4H10. 

If you count all the carbon atoms you will discover, they are four while that of hydrogen is 10.Thus, the name of the compound is ISOBUTANE [I -BUTANE]; it is also called 2 - methyl propane. Isobutane is used majorly as petrol additive in refineries; it is used in the production of isooctane, which is a octane gasoline component that enhances the octane rating and anti-knock properties of gasoline.  

Explanation:

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The table shows the mass and boiling point of some substances.
Westkost [7]

N is the unit of force. It stands for Newton.


M is the unit of length.


It stands for Meter.


It is the basic difference between the two units N and M.


Answer: N - Newton; M - Meter


Shoutout to: @Sidyandex



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5 0
3 years ago
The weight of an object _____.
Butoxors [25]

Answer:

c

Explanation:

and that's bc it will not share stay the same

5 0
3 years ago
W + BgCz2 --&gt; WCz + Bg<br> Balance this equation
yanalaym [24]

Answer: W + BgCz2 arrow WCz + Bg

2 W + BgCz2 arrow  2 WCz + Bg

Explanation:

Cz has 2 so you balcne the other side of WCz.

Since you Balcanes the Cz you changed the W and you Balcanes the other W on the left side.

3 0
3 years ago
g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole
Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

3 0
3 years ago
How many grams of hydrochloric acid will react completely with a block of gold is 3.2 cm by 3.8 cm by 2.8 cm, if the density of
JulijaS [17]
Answer:
mass of HCl = 243.5426 grams

Explanation:
1- we will get the mass of the reacting gold:
volume of gold = length * width * height
volume of gold = 3.2 * 3.8 * 2.8 = 34.048 cm^3 = 34.048 ml<span>
density = mass / volume
Therefore:
mass = density * volume
mass of gold = </span>19.3 * 34.048 = 657.1264 grams

2- we will get the number of moles of the reacting gold:
number of moles = mass / molar mass
number of moles = 657.1264 / 196.96657 
number of moles = 3.3362 moles

3- we will get the number of moles of the HCl:
First, we will balanced the given equation. The balanced equation will be as follows:
Au + 2HCl ......> AuCl2 + H2
This means that one mole of Au reacts with 2 moles of HCl.
Therefore 3.3362 moles will react with 2*3.3362 = 6.6724 moles of HCL

4- we will get the mass of the HCl:
From the periodic table:
molar mass of H = 1 gram
molar mass of Cl = 35.5 grams
Therefore:
molar mass of HCl = 1 + 35.5 = 36.5 grams/mole
number of moles = mass / molar mass
Therefore:
mass = number of moles * molar mass
mass of HCl = 6.6724 * 36.5
mass of HCl = 243.5426 grams

Hope this helps :)
4 0
3 years ago
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